How to deserialize a JSON document witharduinojson.

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I want to deserialize this JSON and get name,issues,totalCount in the Serial monitor.But I get only 0 as the output...

JavaScript

{
"name": "ArduinoJson",
"stargazers": {
"totalCount": 3415
},
"issues": {
"totalCount": 21
}
}

What is the error in my code?

What I have tried:

C++

#include <ArduinoJson.h>
DynamicJsonDocument doc(2000);
String j;

const char* name = doc["name"];
long stars = doc["stargazers"]["totalCount"];
int issues = doc["issues"]["totalCount"];

void setup() {
  Serial.begin(9600);
}

void loop() {
 if (Serial.available()){
  j=Serial.readString();
   deserializeJson(doc,j);
 }

Serial.println(name);   
Serial.println(stars);
Serial.println(issues);

 delay(1000);

}

Posted 17-Feb-20 15:40pm

Member 13358124

Updated 21-Dec-20 8:22am

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2 solutions

Solution 2

Serial.println( doc["name"]);
Serial.println( doc["stargazers"]["totalCount"]);
Serial.println( doc["issues"]["totalCount"]);

Posted 21-Dec-20 8:22am

Member 15027050

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CPallini · Accepted Answer · 2020-02-17T21:25:00

Solution 1

I'm not an expert, but...
Form this library sample code JsonParserExample.ino | ArduinoJson 6[^] it is apparent that first you must deserialize and then you can fetch the values (e.g. stars = doc["stargazers"]["totalCount"];).
The sample code also shows you how to handle deserialization errors.

Posted 17-Feb-20 21:25pm

CPallini

Comments

Member 13358124 18-Feb-20 7:54am

Thank you...

CPallini 18-Feb-20 8:07am

You are welcome.