Can someone explain me this code and desired output?

Question

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Python

x=90
def harry():
    x=20
    def rohan():
        global x
        x=88

     print("before calling rohan",x)
     rohan()
     print("after calling rohan", x)

harry()
print(x)

What I have tried:

why this is printing 90 instead of 88?

Posted 23-Jul-20 20:06pm

Member 14897676

Updated 23-Jul-20 20:57pm

v3

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2 solutions

Solution 1

Because your indentation doesn't match:

Python

def harry():
    x=20
    def rohan():
        global x
        ...

     print("before calling rohan",x)
     ...

You have extra whitespace before the "print" instruction.
As a result, it doesn't run.
Remove those from the three lines and it prints "88"

Don't mix tabs and spaces: set your editor to always replace tabs as it'll save you a LOT of grief later. Python indentation is very important, and a TAB is not the same as a SPACE - if you don't "just use spaces" then what looks identical turns out not to be as far as Python is concerned.

Posted 23-Jul-20 20:16pm

OriginalGriff

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Sandeep Mewara · Accepted Answer · 2020-07-23T20:57:00

Output of above:

('before calling rohan', 20)
('after calling rohan', 20)
88

Execution sequence:
1. harry() called
2. print("before calling rohan",x) => x=local x value that is not modified so far => 20
3. rohan() called => updates global x value to 88
4. print("after calling rohan", x) => local x value is still as it was - not modified => 20
5. print(x) called => global x value is checked which was set to 88 by rohan() => 88