Write a program to print 20 terms of series 3n+2 .stop as soon as multiple of 4 is encountered. (N is user input).

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here is what i have tryied but i cant find the solution plz help

What I have tried:

package com.dibyendu;


import java.util.Scanner;

public class assign11 {
    public static void main(String[] args) {
        //  n = 1
        // 3n + 2 = 5 Not a multiple of 4
        //  n = 2
        // 3n + 2 = 8 is a multiple of 4 ... stop

        Scanner sc = new Scanner(System.in);
        int n = sc.nextInt();
        System.out.println("Enter a number");
        int sum;
        for (; sum % 4 != 0; n++)

            sum = 3 * n + 2;
        System.out.println(sum);


    }
}

Posted 24-Jul-20 19:52pm

Callme Dibyendu

Updated 24-Jul-20 20:22pm

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Richard MacCutchan 25-Jul-20 4:56am

Same answer as yesterday.

1 solution

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OriginalGriff · Accepted Answer · 2020-07-24T20:22:00

Solution 1

Read the question carefully.
It says that you need to read a value from the user into a variable called n . Do you do that?
Then you need to a loop that runs 20 times - to print 20 terms.
Inside the loop, calculate 2 * n + 1 and store it in n
Print the new value of n
Check n: if it is a multiple of 4, exit the loop.

It's not complicated, just do each =step as a separate item, test it, and when it works properly, move on to the next step.

Give it a try!

Posted 24-Jul-20 20:22pm

OriginalGriff

Comments

Callme Dibyendu 25-Jul-20 3:55am

thank you very much sir i got it please check sir is it correct or not

package com.dibyendu;

import java.util.Scanner;

public class assign11 {

public static void main(String[]args) {
Scanner sc = new Scanner(System.in);
System.out.println("enter the number");
int n =sc.nextInt();
for(int sum;n<=20;n++)
{
sum=3*n+2;
System.out.println(sum);
if(sum%4==0){
break;
}

}
}
}

OriginalGriff 25-Jul-20 3:58am

Stop panicking, start thinking.
Look at what I said, and think about each step in turn.
You've done the first one - read the input from the user.
Have you done the second? Really? Are you sure?

Don't try to "jump ahead" - do each bit in sequence and make sure it works before you move on - that way you don't have so many complications to think about each time.

Callme Dibyendu 25-Jul-20 4:11am

sir i need help can i contact u in other platform please sir in telegram or anywhere please sir please....

Callme Dibyendu 25-Jul-20 4:12am

sir your are great please sir give me opportunity to be your student i want to learn something from you

OriginalGriff 25-Jul-20 4:27am

Sorry, but I can't: we are all volunteers here, most of us with "actual jobs" that take precedence (they pay the rent and food bills!) and mentoring someone is a massive amount of time and energy that I just don't have to spare. And I get this request a couple of times a month - I couldn't take one everyone even if I wanted to! You already have a teacher and probably a course book to follow - try working with that and see how far you can get.