Python

n = 5 h = 0 d = int(n/2)+1 for r in range(0, n): s='' for c in range(1, n+1): if r<d: h = r*2 elif r==d: h = d else: h = int(d/3) s+=str(h*n+c) + ' ' print(s)

Result:

1 2 3 4 5 11 12 13 14 15 21 22 23 24 25 16 17 18 19 20 6 7 8 9 10

Print the following pattern in python for the given number of rows.

Pattern for N = 5

1 2 3 4 5

11 12 13 14 15

21 22 23 24 25

16 17 18 19 20

6 7 8 9 10

**What I have tried:**

Pattern for N = 5

1 2 3 4 5

11 12 13 14 15

21 22 23 24 25

16 17 18 19 20

6 7 8 9 10

Python

n = int(input()) upper = int(n/2)+1 lower = n - upper start_i_lower = 0 for i in range(0, upper): if i != 0: i = i + i start = n*i + 1 end = start + n for j in range(start, end): print(j, end =" ") start_i_lower = i print() start_i_lower -= 1 for i in range(0, lower): if(n%2 == 0): start_i_lower -= 1 start = n*(start_i_lower-1) + 1 end = start + n for j in range(1, n+1): print(j+n, end =" ") print()

Comments

Try this:

Result:

Python

n = 5 h = 0 d = int(n/2)+1 for r in range(0, n): s='' for c in range(1, n+1): if r<d: h = r*2 elif r==d: h = d else: h = int(d/3) s+=str(h*n+c) + ' ' print(s)

Result:

1 2 3 4 5 11 12 13 14 15 21 22 23 24 25 16 17 18 19 20 6 7 8 9 10

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Comments

CPallini
1-Oct-20 3:31am

5.

Maciej Los
1-Oct-20 3:51am

Thank you, Carlo. I'm exploring new programming area and i'm truly fascinated ;)

CPallini
1-Oct-20 3:58am

:thumbsup:

The more optimized version will be:

Python

n = 5 h = 0 d = int(n/2)+1 for r in range(0, n): s='' if r<d: h = r*2 elif r==d: h = d else: h = int(d/3) for c in range(1, n+1): s+=str(h*n+c) + ' ' print(s)

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v2

n = int(input( )) P = 1 for i in range(1, n + 1): for j in range(P, P + n): print(j, end=" ") print() if i == ((n + 1)//2): if (n % 2) != 0: P = n*(n - 2) + 1 else: P = n * (n - 1) + 1 elif i > ((n + 1) // 2): P = P - 2 * n else: P = P + 2 * n

It's a pretty simple and straightforward question. Sure a little tricky one

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v2

Comments

CHill60
24-Jun-22 7:33am

A word to the wise - answering "old" questions that already have solutions is often perceived as "rep point hunting" and in the past has led to accounts being suspended. My advice is to stick to posting solutions to more recent posts, and if there is already a solution posted, make sure you add commentary to explain why yours is better/different/an alternative approach.

n = int(input()) if n % 2 == 0: n1 = int(n/2) n2 = n-n1 else: n1 = int(n/2)+1 n2 = n-n1 x = 1 i = 1 i1 = 1 #Upper pattern while i <= n1: for j in range(1, n+1): print(x, end=" ") x = x+1 print() if i == n1: break x = x+n i = i+1 #Lowe Pattern if n % 2 == 0: while i1 <= n2: for k in range(1, n+1): print(x, end=" ") x = x+1 x=x-(2*n) print() i1 = i1+1 x = x-n y=y+1 else: while i1 <= n2: x = x-(2*n) for k in range(1, n+1): print(x, end=" ") x = x+1 x=x-n print() i1 = i1+1

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v2

n = int(input())

if n%2 == 0:

m = n//2

else:

m = n//2+1

for i in range(1, m+1, 1):

for j in range(1, n+1, 1):

print(2*n*(i-1)+j, end ='')

print(' ',end = '')

print()

r = n - m

for i in range(r, 0, -1):

for j in range(1, n+1, 1):

print((2*i-1)*n + j, end ='')

print(' ', end ='')

print()

if n%2 == 0:

m = n//2

else:

m = n//2+1

for i in range(1, m+1, 1):

for j in range(1, n+1, 1):

print(2*n*(i-1)+j, end ='')

print(' ',end = '')

print()

r = n - m

for i in range(r, 0, -1):

for j in range(1, n+1, 1):

print((2*i-1)*n + j, end ='')

print(' ', end ='')

print()

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