How to find the type of user input in Python

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Hi!
I'm learning Python and I'm stuck already :)

If user inputs for example 8 it should say that number is integer, otherwise, if user inputs 5.62 it will display, that number is float.

Thank you!

What I have tried:

For example, I have tried the following code:

Python

num_a = float(input("Enter first number: "))
if num_a % 10 == 0:
      print(f"Number {num_a} is integer")
else:
      print(f"Number {num_a} is float")

Posted 9-Dec-20 0:41am

Zaur Bahramov

Updated 9-Dec-20 1:02am

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2 solutions

Solution 2

A simple method would be to read it in as a string and then test if the string contains a decimal indicator. You can then convert it to float or int as appropriate.

Python

number = input("Enter a number: ")
if '.' in number:
    print("Number is a float")
else:
    print("Number is an integer")

Posted 9-Dec-20 1:02am

Richard MacCutchan

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Richard Deeming · Accepted Answer · 2020-12-09T00:50:00

Solution 1

Your code is testing whether the entered number is divisible by 10.

To test whether a number is an integer, try comparing it to its truncated version:

Python

if num_a == math.trunc(num_a):

You'll need to make sure you have import math at the top of your code.

Otherwise, if you have to stick with the modulo operator, test whether the number is divisible by 1 instead of 10:

Python

if num_a % 1 == 0:

Posted 9-Dec-20 0:50am

Richard Deeming

Updated 9-Dec-20 1:02am

v2

Comments

Zaur Bahramov 9-Dec-20 6:58am

am yet in the first lesson, and i can't use anything except what we have passed. I thought there's some other way. But we have passed type().
But if I use type() it doesn't identify a number, it says it is a string:
num = input("Input a number: ")
print(type(num))

Output: <class 'str'="">

Richard Deeming 9-Dec-20 7:01am

If you have to use the modulo operator, then test whether the number is divisible by 1, not 10:

if num_a % 1 == 0:

Zaur Bahramov 9-Dec-20 7:08am

Great! This is exactly what I needed! Thank you very much!