How to sort by numbers first, then by characters in an array?

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I have a list that I would like to sort by numbers first and then by characters. It would be something like this:

['5Yjb', '5kC7', '79jc', '8v2H', '9J6c', 'Fnyq']

In which case I would need to get '79jc', because it is the only one that has 2 numbers. Another example would be:

['0FZXo7p', '0zyBXOF', '1b5HCW3', '3Nar3Ot']

Where it would return '1b5HCW3'. How would I sort this?

What I have tried:

I have tried to count the number of numbers, but that didn't work. Is there a Python build in function that could do something like this. Sorted sorts only by the first number.

Posted 4-Jan-21 6:07am

Member 14631234

Updated 4-Jan-21 7:53am

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Richard MacCutchan 4-Jan-21 12:33pm

What exactly are you trying to get in the sorted result?

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Richard MacCutchan · Answer 1 · 2021-01-04T06:36:00

Solution 1

This may be useful: Built-in Functions — sorted()[^].

And this: Sorting HOW TO — Python 3.7.9 documentation[^].

Posted 4-Jan-21 6:36am

Richard MacCutchan

Updated 4-Jan-21 6:38am

v2

Comments

Maciej Los 4-Jan-21 12:43pm

5ed!

Richard MacCutchan 4-Jan-21 15:43pm

Thanks Maciej. We, in the UK, have just been put into national lockdown again - stay at home unless essential. How are things in Poland?

Maciej Los 4-Jan-21 16:00pm

Sadly, but... till 17. January the same.

Patrice T · Answer 2 · 2021-01-04T07:53:00

Quote:
I have a list that I would like to sort by numbers first and then by characters. It would be something like this:

Python
['5Yjb', '5kC7', '79jc', '8v2H', '9J6c', 'Fnyq']

This is the result of standard sort of strings.
You forgot to tell what is wrong with this list.

Quote:
In which case I would need to get '79jc', because it is the only one that has 2 numbers.

You forgot to tell what you want to do with this string.

We can't help you if you don't tell exactly what you want.