Click here to Skip to main content
14,969,782 members
Please Sign up or sign in to vote.
1.00/5 (2 votes)
See more:
if (x === 0) {
y = y + 2;
console.log(y);
}
else {
y = y + 3;
console.log(y);
}

What I have tried:

Quote:
if (x === 0) {
y = y + 2;
console.log(y);
}
else {
y = y + 3;
console.log(y);
}
Posted
Updated 7-Jan-21 23:42pm

That's not Java, it looks Javascript.
I wonder why do you think you need to optimize such a piece of code. It works well as it stands.
   
Well, you could try:
Java
y += (x === 0) ? 2 : 3;
console.log(y);
   

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)




CodeProject, 20 Bay Street, 11th Floor Toronto, Ontario, Canada M5J 2N8 +1 (416) 849-8900