How do I resolve the following error: parse error: syntax error, unexpected '$conn' (T_VARIABLE) in C:\xampp\xampp\htdocs\index.php on line 6

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<?php
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "course_enrolment";
 $conn = mysqli_connect($servername, $username, $password, $dbname);
if (!$conn) {
    die("Connection failed: " . mysqli_connect_error());
}
?>
<!DOCTYPE html>
<html>
<head>
<title>Minerva Timetable</title>
</head>
<body>
<h1>The Minerva bus company Timetable</h1>
<?php

What I have tried:

I've tried to google help which suggests I have a semi colon missing but it's not, any help greatly received. 1st year college student. I'm using Notepad++ and xampp

Posted 24-Jun-21 10:10am

Stitchcody

Updated 19-Jul-22 23:26pm

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SeeSharp2 24-Jun-21 16:38pm

Maybe the space before $conn? I don't do php but your code looks good, according to w3schools, https://www.w3schools.com/php/func_mysqli_connect.asp

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Wendelius · Answer 1 · 2021-06-24T10:40:00

Solution 1

Have you tried using mysqli_connect_errno() to check if connection failed. Something like

PHP

...
if (mysqli_connect_errno() <> 0) {
    die("Connection failed: " . mysqli_connect_error());
}
...

Posted 24-Jun-21 10:40am

Wendelius