Php does not work when the codes I run separately are combined

Question

1.00/5 (1 vote)

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I ran this code and it worked

<!DOCTYPE html>
<html>
<body>
<?php

$pizza  = "slice1 slice2 slice3 slice4 slice5 slice6";
$slices = explode(" ", $pizza);

echo " $slices[0] <br> "  ; // slice1
echo $slices[1]; // slice2

?>
</body>
</html>

and when i run this code it worked the same way

<!DOCTYPE html>
<html>
<body>
<?php
// Check if the type of a variable is integer   

$pizza  = "slice1 slice2 slice3 slice4 slice5 slice6";

$x = substr_count($pizza , ' ')+1 ;

echo "$x <br>";

?>  
</body>
</html>

I don't know, maybe I made a string integer error, I thought I should define it from the beginning, so I searched this.

<?php
$x = 5985;
var_dump(is_int($x));

$x = 59.85;
var_dump(is_int($x));
?>

finally i wrote the following code but it gives me error

<!DOCTYPE html>
<html>
<body>

<?php

settype($x, "integer"); 
settype($y, "integer"); 



$pizza  = "slice1 slice2 slice3 slice4 slice5 slice6";
$slices = explode(" ", $pizza);

$y =  substr_count($pizza , ' ')+1

for( $x = 0 ; $x <=  $y ; $x++ ) {



echo  $slices[$x] <br>  ;

}

?>

</body>
</html>

PHP Parse error: syntax error, unexpected 'for' (T_FOR) in /home/6TZO55/prog.php on line 17

What I have tried:

HTML

<!DOCTYPE html>
<html>
<body>

<?php

settype($x, "integer"); 
settype($y, "integer"); 



$pizza  = "slice1 slice2 slice3 slice4 slice5 slice6";
$slices = explode(" ", $pizza);

$y =  substr_count($pizza , ' ')+1

for( $x = 0 ; $x <=  $y ; $x++ ) {



echo  $slices[$x] <br>  ;

}

?>

</body>
</html>

Posted 27-Jul-21 20:04pm

kaixian 6000

Updated 27-Jul-21 22:23pm

Add a Solution

2 solutions

Solution 3

<!DOCTYPE html>
<html>
<body>

<?php

settype($x, "integer"); 
settype($y, "integer"); 



$pizza  = "slice1 slice2 slice3 slice4 slice5 slice6";
$slices = explode(" ", $pizza);

$y =  substr_count($pizza , ' ')+1;

for( $x = 0 ; $x <=  $y ; $x++ ) {



echo  $slices[$x]  ;

}

?>

</body>
</html>

Posted 27-Jul-21 22:23pm

kaixian 6000

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OriginalGriff · Accepted Answer · 2021-07-27T20:27:00

Solution 1

You are missing a semicolon:

PHP

$y =  substr_count($pizza , ' ')+1
                                  ^
                                  |
for( $x = 0 ; $x <=  $y ; $x++ ) {

Add it, and the error will go away.

Semicolons are important in PHP: every instruction must end with a semicolon (or a set of curly brackets in the case of flow control)

Posted 27-Jul-21 20:27pm

OriginalGriff

Comments

kaixian 6000 28-Jul-21 4:21am

thank you 😁 . i use this site but i deleted a which put a new step solution newline . but i delete and this worked

i use this site

https://www.w3schools.com/php/phptryit.asp?filename=tryphp_regex_replace