failed to open dir: No such file or directory

Question

2.50/5 (2 votes)

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PHP

$path= "/dropdown/";
 if(!is_dir($path))
 {
    echo "improper directory";
 }
 else
 {
    $zip = new ZipArchive;
    $zip->open('/file.zip', ZipArchive::CREATE);
if (false !== ($dir = opendir($path)))
     {
         while (false !== ($file = readdir($dir)))
         {
             if ($file != '.' && $file != '..')
             {
                       $zip->addFile($path.DIRECTORY_SEPARATOR.$file);

             }
         }
     }
     else
     {
         die('Can\'t read dir');
     }
$zip->close();

i cant open the directory and please give suggestion for open the directory
and i am working php in ubuntu platform for different type open the directory,
give the suggestion

Posted 22-Jan-13 1:37am

prabu kanagaraj

Updated 22-Jan-13 1:39am

v2

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Sergey Alexandrovich Kryukov · Answer 1 · 2013-01-22T05:14:00

Are you sure you really need "/file.zip"? I'm sure you don't.

Even with a desktop application, this is totally unreasonable; it would mean that you are working in a root directory of a disk. In general, there are no situations where hard-coded path names could be useful. If this is a Web application, you cannot do it at all. For apparent security reasons, HTTP server will only allow you to work with the directories under the rood directory of a give site.

If you used, say, "./file.zip" instead, it would be legitimate location, relative to the current working directory.

—SA