Too few parameters in call to 'patient::search(patient *)'

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#include<iostream.h>
#include<conio.h>
#include<stdio.h>
#include<string.h>


class Patient
{
	int id;
	char name[30];
	float age;
	char sex[6];
	int room_no;

	public:
		void show();
		void add();
		void search(Patient*p);
};


void Patient::show(){
	cout<<"\n Patient Name :  "<<name;
	cout<<"\n Patient ID :  "<<id;
	cout<<"\n Patient Age  :  "<<age;
	cout<<"\n Sex          :  "<<sex;
	cout<<"\n Room No.     :  "<<room_no;
	cout<<"\n Patient name has been registered";
}


void Patient::add(){
	cout<<"\n -------------------------------";
	cout<<"\n Enter Patient Details";
	cout<<"\n -------------------------------";
	cout<<"\n Patient Name :  ";
	cin>>name;
	cout<<"\n Patient ID :  ";
	cin>>id;
	cout<<"\n Patient Age  :  ";
	cin>>age;
	cout<<"\n Sex          :  ";
	cin>>sex;
	cout<<"\n Room No.     :  ";
	cin>>room_no;

}


void Patient::search(Patient*p)
	{
	int i,confirm=0,iid;
	cout<<"\nEnter Patient's ID :  ";
	cin>>iid;
	for(i=0;i<10;i++)
	{
		if(iid==p[i].id)
		{
			confirm=1;
			break;
		}
	}
	if(confirm==1)
	{
		cout<<"Patient is in room number "<<p[i].room_no;
	}
	else
	{
		cout<<"Patient not found";
	}
}


void main(){
	Patient p[10];
	clrscr();
	p[1].add();
	p[1].show();
	p[1].search(p);
	getch();
	int n;
	do{
		cout<<"Welcome to Hospital Patient Management"<<endl;
		cout<<"Press 1 >>Add Patient\n";
		cout<<"Press 2 >>Search for Patient\n";
		cout<<"\nEnter Number :  ";
		cin>>n;
		switch(n){
			case 1:
				p[1].add();
				break;
			case 2:
				p[1].search();
				break;
			case 3:
				return;
		}
	}while(n!=3);
	cout<<"Thank You...!";
}

What I have tried:

Tried everything cant understand please help......

Posted 14-Mar-22 2:38am

Krish Bari

Updated 14-Mar-22 5:57am

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2 solutions

Solution 3

Your code is very C-like.
You could take more advantage from C++ features and library.
Try, for instance:

C++

#include<iostream>
#include <vector>
#include <algorithm>
using namespace std;

class Patient
{
  int id;
  string name;
  //...

public:
  Patient( int id, string name /*, ...*/):id(id), name(name){}
  int get_id() const { return id;}
  friend ostream & operator <<(ostream & os, const Patient & p); //i.e.  'show'
};

ostream & operator << (ostream & os, const Patient & p)
{
  os << "\n Patient Name : " << p.name;
  os << "\n Patient ID : " << p.id;
  //..
  return os;
}

void add_patient(vector <Patient> & vp)
{
  string name;
  int id;
  cout<<"\n -------------------------------";
  cout<<"\n Enter Patient Details";
  cout<<"\n -------------------------------";
  cout<<"\n Patient Name :  ";
  cin>>name;
  cout<<"\n Patient ID :  ";
  cin >> id;
  //..
  vp.emplace_back(Patient(id, name));
}


void search_patient( const vector <Patient> & pv, int id)
{
  auto it = find_if(pv.begin(), pv.end(), [id](Patient p){ return p.get_id() == id;});
  if ( it == pv.end() )
    cout << "not found.\n";
  else
    cout << "found: " << *it << "\n";
}


int main()
{
  vector<Patient> pv;

  int n;
  do
  {
    cout<<"Welcome to Hospital Patient Management"<<endl;
    cout<<"Press 1 >>Add Patient\n";
    cout<<"Press 2 >>Search for Patient\n";
    cout<<"\nEnter Number :  ";
    cin >> n;
    switch(n)
    {
      case 1:
        add_patient(pv);
        break;
      case 2:
        {
          int id;
          cout << "\nplease enter the id : ";
          cin >> id;
          search_patient(pv, id);
        }
        break;
      case 3:
        break;
    }
  }while(n<3);
  cout<<"Thank You...!";
}

Posted 14-Mar-22 5:57am

CPallini

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CHill60 · Accepted Answer · 2022-03-14T02:53:00

Look at your case statement

C++

case 2:
				p[1].search();

You have not defined any override of search that does not take any parameters. Look at your Patient class

C++

class Patient
{
	int id;
	char name[30];
	float age;
	char sex[6];
	int room_no;

	public:
		void show();
		void add();
		void search(Patient*p);
};

You could get around it with

C++

case 2:
				p[1].search(&p[1]);

but I think you need to do some rethinking