Fatal error: uncaught mysqli_SQL_exception

Question

1.00/5 (1 vote)

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stmt_init();

if(!$stmt->prepare($sql)) {
die("SQL error: " . $mysqli->error);
}

$stmt->bind_param("sss",
$_POST["username"],
$_POST["email"],
$password_hash);

$stmt->execute();

echo"Signup successful";

?>

What I have tried:

Fatal error: Uncaught mysqli_sql_exception: You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near '. VALUES(?, ?, ?)' at line 2 in C:\xampp\htdocs\myPortfolio\signup.php:38 Stack trace: #0 C:\xampp\htdocs\myPortfolio\signup.php(38): mysqli_stmt->prepare('INSERT INTO use...') #1 {main} thrown in C:\xampp\htdocs\myPortfolio\signup.php on line 38

Posted 11-Aug-22 1:56am

Hayford Agyei

Updated 11-Aug-22 2:05am

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Comments

Richard MacCutchan 11-Aug-22 8:02am

We need to see the actual SQL that you are generating; we cannot guess what you have written.

Richard Deeming 11-Aug-22 9:51am

At a guess, based on the "near '. VALUES(?, ?, ?)'" in your error message, you have a stray . character in your SQL.

But without seeing the actual query you're using, that's just a guess.

Richard MacCutchan 11-Aug-22 11:35am

Well spotted.

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OriginalGriff · Answer 1 · 2022-08-11T02:05:00

Without knowing what the SQL statement is, we can;t help you - and we can;t see what $sql contains.

So start with the debugger (PHP: Debugging in PHP - Manual[^]) and find out exactly what the command string is.
Then look closely at that - the error message seems to say that there is a decimal point immediately before the keyword VALUES that shouldn't be there.