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If “number” is an even number, store the binary representation in the right order.
If “number” is an odd number, store the binary representation in the reverse order

What I have tried:

include <stdio.h>
int main() {
int num;
printf("Enter an integer: ");
scanf("%d", &num);

// true if num is perfectly divisible by 2
if(num % 2 == 0)
printf("%d is even.", num);
else
printf("%d is odd.", num);

return 0;
}
Posted
Updated 9-Oct-22 9:11am
Comments
merano99 9-Oct-22 16:18pm    
There is a source code approach, but no question?
You can already see if the number is even or odd, only the two functions that do the conversion are missing. It would also be nice if you could make the source code easier to read with the appropriate code tags.

1 solution

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