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I have a number input field and a submit button. The task: when I click the button push the number to the $a array. The number is $weight.

But when I want to push the following number it replaces the number at index 0.

Why?

What I have tried:

<pre lang="PHP"><!DOCTYPE html>
<html lang="en">

<head>
    <meta charset="UTF-8" />
    <meta http-equiv="X-UA-Compatible" content="IE=edge" />
    <meta name="viewport" content="width=device-width, initial-scale=1.0" />
    <title>Weight loss app</title>
</head>

<body>
    <?php
    $a = [];
    if (isset($_POST['submit'])) {
        $weight = $_POST['weight'];
        array_push($a, $weight);
    }
    print_r($a);
    ?>
    <form action="" method="post">
        <input type="number" name="weight" id="weight">
        <button type="submit" name="submit">Upload weight</button>
    </form>
</body>

</html>
Posted
Updated 26-Jan-23 2:29am

1 solution

Your array $a is declared as being empty which is why it takes the first value at your index 0.

If you add a value, say
$a = [12];
and then run your code, notice that 12 is now at index 0 and weight follows the next then at index 1.

You can also run a test on adding another variable, say $b -
$a = [];
$b = 18;
    if (isset($_POST['submit'])) {
        $weight = $_POST['weight'];
        array_push($a, $b, $weight);
    }
    print_r($a);


Your print will return
Array {[0] = 18 [1] = 10 (or whatever value was passed for $weight}
 
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