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I have written a code to alphabetically sort a string. I have to find magic name, i.e. alphabetically sorted string. It is as under:
import java.util.*;
import java.io.*;
import java.lang.*;
public class magicnum{
    
    public static void main(String args[]) throws java.util.NoSuchElementException
{
    Scanner sc=new Scanner(System.in);
   
     System.out.println("Enter a string value: ");
      String st = sc.nextLine();
     int j = 0;
      char temp = 0;
      char[] character = st.toCharArray();
      for(int i=0; i < character.length; i++) {
         for(j=0; j < character.length; j++) {
            if(character[j] > character[i]) {
               temp = character[i];
               character[i] = character[j];
               character[j] = temp;
            }
         }
      }
      System.out.println("After Sorting:");
      
        String str1=new String(character);
System.out.println("Magic name is:"+str1);
    
      

    
}
}

Is there any way in which the same code can be written without using toCharArray()?

What I have tried:

import java.util.*;
import java.io.*;
import java.lang.*;
public class magicnum{
    
    public static void main(String args[]) throws java.util.NoSuchElementException
{
    Scanner sc=new Scanner(System.in);
   
     System.out.println("Enter a string value: ");
      String st = sc.nextLine();
     int j = 0;
      char temp = 0;
      char[] character = st.toCharArray();
      for(int i=0; i < character.length; i++) {
         for(j=0; j < character.length; j++) {
            if(character[j] > character[i]) {
               temp = character[i];
               character[i] = character[j];
               character[j] = temp;
            }
         }
      }
      System.out.println("After Sorting:");
      
        String str1=new String(character);
System.out.println("Magic name is:"+str1);
    
      

    
}
}
Posted
Updated 2-Feb-23 21:55pm

1 solution

Quote:
Is there any way in which the same code can be written without using toCharArray()?
Yes, use a StringBuilder (Java Platform SE 7 )[^].
 
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