How do I pass the array and its size to a function that determines and displays the smallest, largest and the average

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1.00/5 (1 vote)

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C++

I don't know how to do this problem

What I have tried:

I prompted the user to enter the 10 values

Posted 20-Feb-23 7:07am

Botshelo Phake

Updated 20-Feb-23 8:29am

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Rick York · Answer 1 · 2023-02-20T07:16:00

The easiest way is to use the STL container std::vector. I will assume that is not an option since you are asking this question. Here is one way to do it, assuming the data is of type double.

C++

const int ArraySize = 10;

typedef double Array[ ArraySize ];

// wrap this all up in a structure

typedef struct structArrayStr
{
    int     Size;
    Array   Data;
} ArrayStr;

Now you can declare an instance of an ArrayStr, initialize it, and pass it by reference to a your function.

Alternatively, you don't have to use the structure at all. You can pass the array and its size to the function as separate parameters.

merano99 · Answer 2 · 2023-02-20T08:01:00

Solution 2

In C++ you can pass an array like this:

C++

int myfkt(int* myarr, int n);

int myarr[] = { 16, 2, 77, 40, 12071 };
int n = sizeof(myarr)/sizeof(myarr[0]);

int result = myfkt(myarr, n);

Posted 20-Feb-23 8:01am

merano99

Updated 20-Feb-23 8:05am

v3

CPallini · Answer 3 · 2023-02-20T08:29:00

This way:

C++

#include <iostream>
using namespace std;

void show_stats( double ad[], size_t size)
{
  // show the stats here...
}

int main()
{
  double ad[]{ 123.5, 42., -1.2E6};
  show_stats( ad, sizeof(ad)/sizeof(ad[0]));
}

or, maybe

C++

#include <iostream>
#include <array>
using namespace std;

template <typename T, size_t N>
  void show_stats( const array<T, N> & a  )
{
  // show stats here
}

int main()
{
  array<double, 3> ad{ 123.5, 42., -1.2E6};
  show_stats( ad );
}

How do I pass the array and its size to a function that determines and displays the smallest, largest and the average

3 solutions

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