Code explanation shape.ordinal?

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Java

Hi I'm new to Java i'm looking at a tetris game code and trying to define every line get an understanding of what actually happens, I've tried putting breakpoints but they just lead me to source code.

enum tetrodd{NoShape, ZShape, SShape, LineShape, 
               TShape, SquareShape, LShape, MirroredLShape };
    private tetrodd pieceShape;
    private int coords[][];
    private int [][][] coordsTable;
    
    public Shape(){
    coords = new int [4][2];
    setShape (tetrodd.NoShape);
    
    }
    public void setShape(tetrodd shape){
    coordsTable = new int[][][] {
            { { 0, 0 },   { 0, 0 },   { 0, 0 },   { 0, 0 } },
            { { 0, -1 },  { 0, 0 },   { -1, 0 },  { -1, 1 } },
            { { 0, -1 },  { 0, 0 },   { 1, 0 },   { 1, 1 } },
            { { 0, -1 },  { 0, 0 },   { 0, 1 },   { 0, 2 } },
            { { -1, 0 },  { 0, 0 },   { 1, 0 },   { 0, 1 } },
            { { 0, 0 },   { 1, 0 },   { 0, 1 },   { 1, 1 } },
            { { -1, -1 }, { 0, -1 },  { 0, 0 },   { 0, 1 } },
            { { 1, -1 },  { 0, -1 },  { 0, 0 },   { 0, 1 } }};
    
    for (int i = 0; i< 4; i++){
    for (int j = 0; j<2; ++j){
    coords[i][j] = coordsTable[shape.ordinal()][i][j];
    }
    }
    pieceShape = shape;
    }

I'm trying to figure out what happens at the line;

coords[i][j] = coordsTable[shape.ordinal()][i][j];

what values gets stored on coords whats the actual value of [shape.ordinal()]

Thanks for your time.
Regards.