how to convert xml file into html in c#

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C#

XPathDocument myXPathDoc = new XPathDocument(@"C:\aa.xml");
           XslTransform myXslTrans = new XslTransform();
           myXslTrans.Load(XSLTFile1);
           XmlTextWriter myWriter = new XmlTextWriter("result.html", null);
           myXslTrans.Transform(myXPathDoc, null, myWriter);
           XPathDocument myXPathDoc = new XPathDocument(@"C:\aa.xml");
           XslCompiledTransform myXslTrans = new XslCompiledTransform();
           myXslTrans.Load("XSLTFile1.xslt");
           XmlTextWriter myWriter = new XmlTextWriter("result.html", null);
           myXslTrans.Transform(myXPathDoc, null, myWriter);

Posted 21-Mar-13 3:47am

akshay niraj

Updated 21-Mar-13 7:01am

Maciej Los

v3

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Comments

joshrduncan2012 21-Mar-13 9:50am

Are you getting any errors? Are you getting any output? What is your question?

ridoy 21-Mar-13 14:57pm

So what is the problem with this code?

Kuthuparakkal 22-Mar-13 0:02am

Added a solution please try.

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Kuthuparakkal · Answer 1 · 2013-03-21T06:33:00

Try this:

C#

public void XslTransform(string xsltFileLocation, string xmlDocumentLocation, string DestinationFilepathName)
{

    //myXslTrans.Load(xsltFileLocation);
    using (MemoryStream ms = new MemoryStream())
    {
        Stream fs = File.OpenRead(xsltFileLocation);

        XPathDocument myXPathDoc = new XPathDocument(xmlDocumentLocation);
        XmlTextReader xtr = new XmlTextReader(fs);

        XslCompiledTransform myXslTrans = new XslCompiledTransform();
        myXslTrans.Load(xtr);

        myXslTrans.Transform(myXPathDoc, null, ms);
        ms.Flush();
        ms.Position = 0;

        FileStream fsNew = new FileStream(DestinationFilepathName, FileMode.Create, FileAccess.Write);
        byte[] bytes = new byte[ms.Length];
        ms.Read(bytes, 0, (int)ms.Length);
        fsNew.Write(bytes, 0, bytes.Length);
        fsNew.Close();
        ms.Close();
    }
}