TextBox In Listview To Add New item with existing items

Question

0.00/5 (No votes)

See more:

I want to show a textbox after the last item in a list view if count of item is not zero. But if zero, textbox must be shown on top.

I tried with setting location of textbox by

C#

TextBox1.location=new point(0,listviewStaticVar.items.count+1);

But I am missing something to setting location pls help.

Thank you.

Posted 27-May-13 0:26am

Anjanee Kumar Singh

Updated 27-May-13 1:47am

lukeer

v2

Add a Solution

Comments

lukeer 27-May-13 7:49am

0) Wrap code between tags like these: <pre lang="c#">YourCodeHere();</pre> (FTFY).
1) One full stop suffices per sentence.

Anjanee Kumar Singh 27-May-13 7:50am

ok

1 solution

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

lukeer · Answer 1 · 2013-05-27T01:43:00

Solution 1

The y-component of TextBox1.Location should be the product of a ListView.Items.Count[^] and the height of one of the items in pixels. You can use ListViewItem.Bounds[^] for that.
Just check if there are any items, and use an y-component of zero if not.

Posted 27-May-13 1:43am

lukeer

Updated 27-May-13 1:44am

v2

Comments

Anjanee Kumar Singh 27-May-13 7:54am

can i get the code so that i can understand better...

Thank you

Anjanee Kumar Singh 27-May-13 8:06am

I did It Like This.............

txtDevTr.Visible = true;
Rectangle r = new Rectangle(position, lvItem.Bounds.Top, end, lvItem.Bounds.Bottom);
txtDevTr.Location = new Point(position - 1,listViewStaticVar.Items.Count+1);
txtDevTr.Show();

lukeer 27-May-13 8:45am

And did it work?
What is position?
What do you use r for?