Record count in mysql using vb.net 2010

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Hi guys,

im having problem with this code, a want to view a count of record into a text box from mysql but when i click the button it will only unload the window and nothings happen. Please help, so far this is my code for your reference.

VB

Imports MySql.Data.MySqlClient

Public Class frm_login
    Private Sub btn_login_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles btn_login.Click
        txt_count.Text = idverifier()
        frm_main.txt_remshd.Text = txt_login.Text
    End Sub

    Private Sub pb_exit1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles pb_exit1.Click
        '  End
    End Sub

    Private Sub txt_login_TextChanged(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles txt_login.TextChanged
        Me.txt_login.CharacterCasing = CharacterCasing.Upper
    End Sub

    Function idverifier() As Integer
        Using sqlconnection As New MySqlConnection(cnString)
            sqlconnection.Open()
            Dim sqlcommand As New MySqlCommand("Select COUNT(*) FROM tbl_account WHERE shd_agent = 'JONATHANT'")
            Return sqlcommand.ExecuteScalar()
            sqlconnection.Close()
        End Using
    End Function
End Class

Posted 27-May-13 9:09am

athan_makubex

Updated 27-May-13 9:52am

v4

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3 solutions

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Maciej Los · Answer 1 · 2013-05-27T09:20:00

Solution 1

Your query should looks like:

SQL

SELECT COUNT(*)
FROM tbl_account
WHERE shd_agent LIKE 'JONA%'

Above query mathes: JONATHAN, JONAHTAN, JONATTHA, etc.

If you want to get exact match:

SQL

SELECT COUNT(*)
FROM tbl_account
WHERE shd_agent = 'JONATHAN'

See here:
http://dev.mysql.com/doc/refman/5.0/en/pattern-matching.html[^]

Posted 27-May-13 9:20am

Maciej Los

Comments

athan_makubex 27-May-13 15:29pm

Hi Maciej Los thank you for your quick response. I tried your suggestion but still when i click the button the window unloads. Any idea why it is hapenning? thanks

Maciej Los 27-May-13 15:33pm

Please, debug your program and tell me in which line what kind of error you are getting...

Maciej Los 27-May-13 16:04pm

OK, i see changes now.
Do you have 2 forms and do you want to pass data between forms?
Do you set DialogResult property for btn_Login button? Which?

athan_makubex · Answer 2 · 2013-05-27T10:16:00

Hi Maciej Los,

I've solved it! thanks for your help. I use this code instead of using function.

VB

Private Sub btn_login_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles btn_login.Click

        Dim con As New MySqlConnection(cnString)
        con.Open()
        Dim cmd As New MySqlCommand("Select Count(*) from tbl_account where shd_agent = 'JONATHAN' ", con)
        Dim i As Integer = cmd.ExecuteScalar()
        cmd = Nothing
        con.Close()
        txt_count.Text = i

End Sub

koray karaman · Answer 3 · 2013-10-27T03:24:00

Solution 3

There is already a solution but, here is an alternative one for interested people;

Record count in DataGridView and MySQLTable, comparing them with each other. I think it will be useful.

http://koraykaraman.com/koray/software/vb-net/record-count-mysql-vb-net.html[^]

Koray

Posted 27-Oct-13 3:24am

koray karaman