Compare two points in windows form

Question

0.00/5 (No votes)

See more:

I have two points I need to compare two points
point p1= new point(100,100);
point p2 = new point(105,103);

i tried if(p1.Equals(p2))
and if(p1==p2)
{
}
both didnt work

please hellp me how to keep some approximation and check two points like p1.x+5 and p1.y+5 or p1.x-5 or p1.Y-5 and compare with p2

Posted 26-Aug-13 10:22am

Member 8780842

Add a Solution

3 solutions

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

lukeer · Answer 1 · 2013-08-26T19:06:00

Two ideas come to my mind. Is one of these what you're looking for?

C#

private bool IsManhattanDistanceWithinTolerance(Point p0, Point p1, float tolerance)
{
    return(
        Math.Abs(p1.X - p0.X) <= tolerance
        && Math.Abs(p1.Y - p1.Y) <= tolerance
    );
}

private bool IsEuclidicDistanceWithinTolerance(Point p0, Point p1, float tolerance)
{
    return( Math.Sqrt(((p1.X - p0.X) * (p1.X - p0.X)) + ((p1.Y - p0.Y) * (p1.Y - p0.Y))) <= tolerance)
}

Dave Kreskowiak · Answer 2 · 2013-08-26T13:33:00

Solution 1

Your code compared instances (references) of two Point objects. Basically, are both references pointing to the same memory location?

You need to compare the X and Y properties of each point separately.

if ((p1.X == p2.X) && (p1.Y == p2.Y))

Posted 26-Aug-13 13:33pm

Dave Kreskowiak

Comments

BillWoodruff 26-Aug-13 21:57pm

Dave, in this case I must disagree with you: two separate declarations of Point Objects created by 'new: do not point to the same locations in memory. A 'Point (under-the-hood a 'Struct) is a Value Type, and is allocated directly on the Stack.

Of course, if In-Line Allocation occurs, where value-types that you expect to see on the stack are copied-over to be used as Properties, or whatever, of reference objects (like a Class, or WinForms Controls): that's the case of in-line allocation, as Albahari said:

"Previously we said that for value-typed local variables, memory is allocated on the stack. So does that mean the newly copied Size struct is also allocated on the stack? The answer is no, because it’s not a local variable! Instead, it’s stored in a field of another object (in this case a form) that’s allocated on the heap. Therefore, it must, too, be allocated on the heap. This mode of storage is called 'in-line'." http://www.albahari.com/valuevsreftypes.aspx

Dave Kreskowiak 26-Aug-13 23:36pm

Man, I have been "eyes-down" in a web project for way too long now...

BillWoodruff · Answer 3 · 2013-08-26T15:35:00

Direct comparison for identical values (all values match) of two separately created Points is built-in to .NET.

Put a TextBox on a Form, and then execute some code like this somewhere:

C#

Point p1 = new Point(100, 100);
Point p2 = new Point(100, 100);

textBox1.Clear();
textBox1.AppendText((p1 == p2).ToString());

You'll see that if all numbers are the same, the result is 'true, and if any number is not the same, the result is 'false.

Was there some other kind of comparison you had in mind here ?

Compare two points in windows form

3 solutions

Solution 3

Solution 1

Solution 2

Add your solution here

Preview 0