Startinfo arguments dcmqrscp

Question

0.00/5 (No votes)

See more:

&I'm trying to run dcmqrscp from c++ visual studio 2012.

using the following code dcmqrscp. exe start normally

Myprocess.start("c:\program\dcmqrscp", "-c c\data\dcmqrscp.cfg" )

Whereas adding a second argument do not start.

Myprocess.start("c:\program\dcmqrscp", "-c c\data\dcmqrscp.cfg -v. > c:\data\dcmqrscp.log")

Do you have any suggestion

Than you
Andrea

Posted 6-Dec-13 21:22pm

Member 10174363

Add a Solution

1 solution

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

Richard MacCutchan · Answer 1 · 2013-12-06T22:14:00

Solution 1

You cannot add redirection of the program's output in that way; that only works when running in a command shell. If you want the output (or input) redirected then you need to set the redirection handles in your STARTUPINFO[^] settings.

Posted 6-Dec-13 22:14pm

Richard MacCutchan