How to read numbers (separated by spaces) into an array in c

#include<stdio.h>
#include<stdlib.h>

int main()
{

int i,j,n;
scanf("%d",&n); // scanning the size of the array
int *a = malloc(n*sizeof(int));
char temp;
for(i=0;i<n;i++) {

scanf("%d%c", &a[i],&temp); // scanning for both the integer and the space(as a character)

if(temp == '\n') // when temp == enter (\n),i.e, when the user presses enter
{

for(i=0;i<n;i++){ // for loop to print the array runs
printf("%d ",a[i]);

}
}
}

}

You just have to use

yourString.Split(' ');

==> an array of string, then convert each of them into integers.

For conversion you should use:

int.TryParse()

If you are using C, you should read the next: http://www.cplusplus.com/forum/beginner/87238/[^]

You should try something like,

#include <stdio.h>
#include <string.h>
#include <stdlib.h>

int main(void)
{
char b[] = "1.5, 2.5,3.5,4.5,5.5,6.5,7.5,,,10.5,11.5,12.5,,,15.5,16.5,17.5,18.5,19.5,20.5\n";
double c[21];
char *pptr = b;
b[strlen(b)-1]=',';
for (int i = 0; i < 21; i++) {
    char *ptr = strchr(pptr, ',');
    if (ptr) {
        *ptr = 0;
        c[i] = atof(pptr);
        pptr = ptr + 1;
        }
    }

for (int i = 0; i < 20; i++){
    fprintf(stdout, "%7.2lf", c[i]);
    }
return 0;
}

-KR