Getting sum of Unique Value

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Hi
I have a table which contains three unique value

SQL

RId CID  Name Value
1    1   Test 2:15
1    1   Test 4:15
2    1   Name 1:00
2    1   Name 2:15

I want sql query to get result as

SQL

RID CID Name Value 
1   1    Test 6:30
2   1    Name 3:15

Unique in RID, CID, Name and Sum of value

value is in time format (01:15 format) but its nvarchar data type

Please help me to achive this

Thanks
Mohan

Posted 13-May-14 0:42am

V Mohan

Updated 13-May-14 3:16am

King Fisher

v2

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_Asif_ 13-May-14 6:50am

I believe this is a duplicate question

V Mohan 13-May-14 6:51am

No

V Mohan 13-May-14 6:54am

Sorry, I got the Sum of all values in a table , But my requirement is need some of Unique record values. Please help me

3 solutions

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_Asif_ · Answer 1 · 2014-05-13T02:31:00

Try this

SQL

DECLARE @TBL TABLE 
(RID  INT,
 CID  INT, 
 NAME VARCHAR(50),
 Data VARCHAR(10));
 
INSERT INTO @TBL
(
	RID,
	CID,
	NAME,
	Data
)
SELECT 1, 1, 'Test', '2:15'
UNION ALL
SELECT 1, 1, 'Test', '4:15' UNION ALL
SELECT 2, 1, 'Name', '1:00' UNION ALL
SELECT 2, 1, 'Name', '2:15'

SELECT distinct TMP.RID, T.CID, T.NAME, cast(TMP.TOTAL_HOURS as varchar(10)) + ':' + cast(TMP.TOTAL_MINS as varchar(10))
FROM
(
select  RID, Sum(DATEPART(hh, CAST(data as DATETIME))) TOTAL_HOURS, Sum(DATEPART(MI, CAST(data as DATETIME))) TOTAL_MINS
from @TBL
group by RID
) TMP INNER JOIN @TBL T ON TMP.RID = T.RID

sankarsan parida · Answer 2 · 2014-05-13T01:03:00

Solution 1

Make a query like following below
when Value is decimal,int

select RID, CID, Name, sum(Value) as Value from table_name group by RID, CID, Name

at the time datetime

SELECT RID, CID, Name, SUM(DATEDIFF(MINUTE, '0:00:00', convert(time, Value, 8))) as totalTime
FROM table_name 
GROUP BY RID, CID, Name

Posted 13-May-14 1:03am

sankarsan parida

Updated 13-May-14 1:42am

v3

Comments

V Mohan 13-May-14 7:07am

Thanks. But its working for me if the value is integer. My problem is the value field is can be time also so i use the below conversion to set sum of time

Convert(time,dateadd(s,SUM(( DATEPART(hh, td.value) * 3600 ) + ( DATEPART(mi, td.value) * 60 ) + DATEPART(ss, td.value)),0)) as Total

But it show the same values not the sum of the values. Please help me to resolve this

[no name] 13-May-14 7:15am

yes like
SUM( ( DATEPART(hh, td.value) * 3600 ) +
( DATEPART(mi, td.value) * 60 ) +
DATEPART(ss, td.value)
) AS total_sec

V Mohan 13-May-14 7:19am

Thanks, But it displays the seperate records as result like below
1 1 Test 2:15
1 1 Test 4:15
But i need result as follow
1 1 test 6:30

Please help

[no name] 13-May-14 7:42am

see it's updated

King Fisher · Answer 3 · 2014-05-13T03:26:00

Run this

SQL

create table ##table(id bigint identity(1,1),name varchar(max) ,value varchar(max))

insert into ##table (name,value) values('King','2:15')
insert into ##table (name,value) values('KIng','4:15')
insert into ##table (name,value) values('Fisher','1:00')
insert into ##table (name,value) values('Fisher','2:15')

select *From ##table

Query

SQL

select name,convert(time,dateadd(s,SUM(
( DATEPART(hh, value) * 3600 ) +
( DATEPART(mi, value) * 60 ) +
 DATEPART(ss, value)),0)) From ##table group by name

Getting sum of Unique Value

3 solutions

Solution 3

Solution 1

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