Public member 'Count' on type 'String()' not found.

Question

0.00/5 (No votes)

See more:

I am getting the above error message on the code shown below. The code is in a public function and I do have correct import statement on the page (Imports System.Linq). No matter what I do I can't get past this bit of code without the error message. Any suggestions would be greatly appreciated.

VB

If sBreadcrumb.Split(".").Count > 1 Then
 root = CInt(sBreadcrumb.Split(".")(1))
 oPage = New SiteManagerPage(CInt(root), Nothing)
End If

Posted 23-May-14 18:05pm

jmawebco

Updated 23-May-14 18:08pm

v2

Add a Solution

Comments

Member 4627922 3-Jul-21 2:38am

But why does this code work?:

Dim strings As String() = {"A", "B"}
Console.WriteLine(strings.Count.ToString)

3 solutions

Solution 2

Array Type does not support Count Property.
Only Collection, List, ... Type does support Count Property.

Use Length property instead Count about Array Types.

Posted 23-May-14 18:23pm

SlaneR

Solution 3

You missed (),

C#

If sBreadcrumb.Split(".").Count() > 1 Then
  root = CInt(sBreadcrumb.Split(".")(1))
  oPage = New SiteManagerPage(CInt(root), Nothing)
 End If

Note that Count() extension method can be used with IEnumerable but Collection types there is Count property and for array types there is Length property. Most collections have a Length or Count property that is more efficient.

When to use Count(). This extension method does have some good uses. If you use a LINQ query expression, or for some other reason have an IEnumerable instance, it is the best way to determine how many elements are present.

The Count method can be used with an argument of type Func. e.g.:

C#

Dim greaterThanTwo As Integer = array.Count(Function(element) element > 2)

Posted 23-May-14 19:04pm

DamithSL

Updated 23-May-14 19:17pm

v3

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

Abhinav S · Accepted Answer · 2014-05-23T18:09:00

Solution 1

Try If sBreadcrumb.Split(".").Length > 1 Then

Posted 23-May-14 18:09pm

Abhinav S