char* to char**

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How can we assign char* to char**??

For example:

C

char ** strArray = (char **)malloc(N*sizeof(char));
char *str ;
std::string st ("Hi there how are you??");
str = new char[st.size()+1];
strcpy(str, st.c_str());

strArray[1] = ??? <-----str (copy str contents to strArray)

Regards,

Abhishek Dey

Posted 4-May-10 9:06am

GPUToaster™

Updated 4-May-10 10:22am

CPallini

v3

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2 solutions

Solution 2

Yes....I made a terrible mistake there. Thanx Pallini.

Posted 4-May-10 17:06pm

GPUToaster™

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HimanshuJoshi 5-May-10 2:51am

Instead of adding answer. Please add a comment next time you want to thank somebody

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Richard MacCutchan · Accepted Answer · 2010-05-04T10:11:00

You have defined strArray as an array of char* (i.e. pointers to character strings) but your allocation is of N * the size of a single character. I suspect what you meant was

C++

char ** strArray = (char **)malloc(N * sizeof(char*));

Then you could use an assignment such as

C++

strArray[1] = str;  // save the address of this string to strArray