javascript array push method overwrites the value in a for loop.

Question

0.00/5 (No votes)

See more:

Hi,
i am using array.push method to add items to an array but every times it gives me last value and not all the values which i am getting from object,

here is my code.

JavaScript

function generatearray(obj)
{
 jsonObjEdt = []; 
 item = {};
for (j = 0; j < obj.length; j++) {
        $.each(obj[j], function (key, value) {
            var id = key;
            var Size = value;
            item[id] = Size;

        });
        jsonObjEdt.push(item);
        } 
}

my obj have 5 items and my jsonObjEdt also get 5 values but all five values are last from the obj. not sure why this happens ?

Posted 3-Jul-14 1:37am

ravikhoda

Add a Solution

1 solution

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

Murali Gowda · Answer 1 · 2014-07-03T01:49:00

Solution 1

Hi,

$.each itself is a loop why are you using for loop over it??

Just use $.each like this,

JavaScript

function generatearray(obj)
{
 jsonObjEdt = []; 
 $.each(obj, function (key, value) {
       jsonObjEdt.push(value); 
    });     
}

this will work for you..

Posted 3-Jul-14 1:49am

Murali Gowda