how to build like query

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Im using stringbuilder to build my where clause.

How to implement a like clause using stringbuilder?.

For example - I want this query executed.
Select * from table where agentName like '@agentName%';

I would like to implement - agentName like '@agentName%' implement which is part of my whereclause.

C#

Strinbuilder sb = new StringBuilder();
sb.Append(agentName LIKE @agentName);
cmd.Parameters.AddWithValue("@agentName",agentName;);

Can you please help?.

Arvind.

Posted 4-Jul-14 21:20pm

Member 10562713

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2 solutions

Solution 1

Try:

C#

StringBuilder sb = new StringBuilder();
sb.Append("SELECT * FROM myTable WHERE ");
...
sb.Append("agentName LIKE @agentName + '%' ");
...
using (SqlCommand cmd = new SqlCommand(sb.ToString(), con))
   {
   cmd.Parameters.AddWithValue("@agentName", agentName);
   ...

Posted 4-Jul-14 21:35pm

OriginalGriff

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Member 10562713 5-Jul-14 4:12am

This didnt work. Im not getting any result from db. Its always Null but I know data is there.

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DamithSL · Accepted Answer · 2014-07-04T23:05:00

Solution 2

C#

sb.Append("agentName LIKE @agentName");

then

C#

cmd.Parameters.AddWithValue("@agentName", agentName +"%");

Posted 4-Jul-14 23:05pm

DamithSL

Comments

Member 10562713 5-Jul-14 5:19am

Thanks! This did the trick :) !!! Appreciated!