resolve file reading issues

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I am using C# to download 2 xml files:

C#

using (FileStream fs = new FileStream(Path.Combine(Properties.Settings.Default.XmlLocation, DateTime.Now.ToString("yyyyMMddHHmm") + " File2.xml"), FileMode.Create))
               {
                   "\n");
                   client2.DownloadFile(location);
                   Program.processLog.Write("XML File 2 Retrieved");
                   fs.Close();
               }

I then parse the XML file as follows:

C#

XmlSerializer deserializer = new XmlSerializer(typeof(DOGS), new XmlRootAttribute("DOGS"));
                   using (XmlReader reader = XmlReader.Create(Path.Combine(Properties.Settings.Default.XmlLocation, DateTime.Now.ToString("yyyyMMddHHmm") + " File2.xml")))
                   {

                       xmlReadFileOne = (DOGS)deserializer.Deserialize(reader);
                       Program.processLog.Write("File 1 Successfully Deserialized");
                       return xmlReadFileOne;  
                   }

The problem I am having is:

If I retrieve the XML file from the server at 15:26

If I then try and read the same XML file at 15:27

I receive an error that file does not exist because the times do not match.

I think its because when I am reading the file with XML reader I am using XMLReader.create, when all I want to do it read the file perhaps? I am not sure??

Also in the directory there are loads of XML files as I download a file every 5 mins, so I need to ensure I read the latest XML file when deserializing.

Please can you help me resolve this?

Posted 8-Jul-14 5:01am

xirokx

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OriginalGriff · Accepted Answer · 2014-07-08T05:11:00

The simple answer is: never retrieve the time twice if you need to use it again: it may well change!

So store it - or even store the filename - as I did in my answer to your previous question:

C#

string fileName = @"D:\MyFolder\" + DateTime.Now.ToString("yyyyMMddHHmmss") + " Dogs.xml";

You then know you are accessing the same file.
If you are doing this in different methods, and you can't pass it from one to the other, then find the latest version - it's just a change on the code I gave you before:

VB

string latest = Directory.GetFiles(@"D:\MyFolder", "* Dogs.xml")
                    .Select(s => new FileInfo(s))
                    .OrderByDescending(fi => fi.CreationTime)
                    .Select(fi => fi.FullName)
                    .FirstOrDefault();