Update variable value in XSLT for-each loop

Question

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I have this XML:

XML

<Root>
  <Employee>
    <Name>Dash</Name>
    <Age>23</Age>
  </Employee>
  <Employee>
    <Name>Gwen</Name>
    <Age>22</Age>
  </Employee>
</Root>

And I need to convert to below XML using XSLT:

<pre lang="xml"><Root>
  <Employee>
    <Name>Dash,Gwen</Name>
    <Age>23,22</Age>
  </Employee>
</Root
>

I am using the for-each loop to get the values of the sub-nodes of the <employee> node.The problem I am facing is I cannot figure out how to store the concatenated values in another temperoary variable in XSLT.I found on many sites that we cannot update the variables in the XSLT, so is there any alternative solution for this?

Posted 14-Sep-14 18:33pm

Darshil H Pandya

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2 solutions

Solution 1

Not sure why you want to screw up a well formed XML document and create something that will be difficult to maintain, but who am I to judge.

Here is one solution.

XML

<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
    xmlns:msxsl="urn:schemas-microsoft-com:xslt" exclude-result-prefixes="msxsl"
>
    <xsl:output method="xml" indent="yes"/>

    <xsl:template match="Root">
      <Root>
        <Employee>
          <Name>
            <xsl:for-each select="Employee">
              <xsl:value-of select="Name"/>
              <xsl:if test="following-sibling::*">
                <xsl:text>,</xsl:text>
              </xsl:if>
            </xsl:for-each>
          </Name>
          <Age>
            <xsl:for-each select="Employee">
              <xsl:value-of select="Age"/>
              <xsl:if test="following-sibling::*">
                <xsl:text>,</xsl:text>
              </xsl:if>
            </xsl:for-each>
          </Age>
        </Employee>
      </Root>
    </xsl:template>

</xsl:stylesheet>

Posted 14-Sep-14 20:51pm

George Jonsson

Updated 14-Sep-14 20:55pm

v2

Comments

_Asif_ 15-Sep-14 3:06am

+5

George Jonsson 15-Sep-14 3:18am

Thank's Syed.

Darshil H Pandya 16-Sep-14 5:26am

You need to optimize your code sir!

George Jonsson 16-Sep-14 5:29am

How do you mean?
It is not my code. I made it in order to help you.
It is your job to optimize.

Darshil H Pandya 16-Sep-14 5:37am

Thank you very much for your efforts.

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Darshil H Pandya · Accepted Answer · 2014-09-15T23:22:00

This is what I figured out:

I hope it will be helpful to others

<xsl:stylesheet version="1.0" 
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>

<xsl:template match="/Root">
    <Root>
        <Employee>
            <Name>
                <xsl:apply-templates select="Employee/Name"/>
            </Name>
            <Age>
                <xsl:apply-templates select="Employee/Age"/>
            </Age>
        </Employee>
    </Root>
</xsl:template>

<xsl:template match="Name|Age">
    <xsl:value-of select="."/>
    <xsl:if test="position()!=last()">
        <xsl:text>,</xsl:text>
    </xsl:if>
</xsl:template>

</xsl:stylesheet>