How to choose a random color from System.Drawing.Color?

As a color has RGB data and all values (red, green and blue) are integers from 0 to 255 (0 and 255 included), you can use the Random class to generate three integers between 0 and 255.

Random rand = new Random();
int max = byte.MaxValue + 1; // 256
int r = rand.Next(max);
int g = rand.Next(max);
int b = rand.Next(max);
Color c = Color.FromArgb(r, g, b);

rand.Next(max); returns an integer from 0 to 255, but we pass max (= 256) as argument because the argument of rand.Next is the exclusive upper bound, so if we use 256 here, it will include 255, but not 256.

More information about Random.Next: http://msdn.microsoft.com/en-us/library/System.Random.Next.aspx[^]

Your answer at How to generate random color names in C#[^].

A simple way for obtaining an opaque color

Random rand = new Random();
int r = rand.Next(256);
int g = rand.Next(256);
int b = rand.Next(256);
Color col = Color.fromArgb(r,g,b);

There's this, but it could use some work.

public static class RandomColor
{
    private static readonly System.Random r ;
    private static readonly System.Reflection.PropertyInfo[] a ;

    static RandomColor
    (
    )
    {
        r = new System.Random() ;

        a = typeof(System.Drawing.Color).GetProperties ( System.Reflection.BindingFlags.Public | System.Reflection.BindingFlags.Static ) ;

        return ;
    }

    public static System.Drawing.Color
    Next
    (
    )
    {
        return ( (System.Drawing.Color) a [ r.Next ( a.Length ) ].GetValue ( null , null ) ) ;
    }
}

The idea is to pass random values to the Color object itself. The following is the documentation for the Random class.

http://msdn.microsoft.com/en-us/library/system.random(v=vs.110).aspx[^]

You can create your own random numbers, and then pass them as values of Red, Green and Blue in the Color object.

Since we're going to work between 0 - 255, so you will use this property on the Random object, Next(int, int).

// create new instance
Random rand = new Random();
// would return between 0 - 255
int randomNumber = rand.Next(0, 255);

Now, you can get these values in three different variables. Then pass them as values to the Color object. Like this

// include namespaces
using System;
using System.Drawing;

// create new instance
Color color = new Color();
// set the values of RED, GREEN and BLUE
color.R = randRed;
color.G = randGreen;
color.B = randBlue;

// use the color here in the code
// as a Color object of System.Drawing namespace.

the best and effiënt way of doing this is:

Random rng = new Random();

Color.FromArgb(rng.next(-16777216, 0);

this will return a random color with 255 as the alpha value;