Need to convert a asp.net c# validation code into clientside Validation(either jquery or javascript)

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C#

public static bool ValidateDigit(string sTrn)
   {
       if (sTrn != "")
       {
           if (sTrn.Length < 9) return false;
           //this function multiplies digits 1,4,7 by 3, digits 2,5,8 by 7, and 3,6,9 by 1, and
           //adds the results together. If the total is evenly divisible by 10, then the check digit is ok
           //otherwise, it is not.  example "good" trn = 263181368

           int[] multipliers = new int[3] { 3, 7, 1 };  //multiply each digit by one of these numbers
           int s = 0;
           int m = 0;

           for (int i = 0; i < 9; i++)
           {
               s += int.Parse(sTrn.Substring(i, 1)) * multipliers[m];
               m = ++m < 3 ? m : 0;  //reset to first multiplier
           }

           return (s != 0 && s % 10 == 0) ? true : false;
       }
       else
           return false;
   }

Posted 29-Oct-14 0:51am

sharonjoy

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Comments

Shemeemsha (ഷെമീംഷ) 29-Oct-14 6:59am

Use this same logic their ..
Any problem ?

sharonjoy 29-Oct-14 7:18am

Didnt workout.How could i initialize ' int[] multipliers = new int[3] { 3, 7, 1 }; ' in jquery.?

Sunita Rana 29-Oct-14 7:42am

for initializing array in javascript see this sample:

<!DOCTYPE html>
<html>
<body>

<p id="demo"></p>

<script>
var numbers= [1, 1, 46];
document.getElementById("demo").innerHTML = numbers[2];
</script>

</body>
</html>

2 solutions

Solution 2

C#

var x = new Array(3, 7, 1);
       var s = 0;
       var m = 0;
       var j = 0;
       for (i = 0; i < 9; i++) {

           if (m == 0)
               j = 3;
           else if (m == 1)
               j = 7;
           else if (m == 2)
               j = 1;

           s += parseInt(vNumbr[i], 10) * j;

           m = ++m;

           if (m >= 3) {
               m = 0
           }

       }
       return (s != 0 && s % 10 == 0) ? true : false;

Posted 29-Oct-14 19:45pm

sharonjoy

Comments

SRS(The Coder) 30-Oct-14 2:18am

thanks for sharing.

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SRS(The Coder) · Accepted Answer · 2014-10-29T04:08:00

Hi sharonjoy,

Here I have created one jQuery method as per your logic, please check this out :-

JavaScript

function ValidateNumber(strNo) {
            if (strNo == '' || strNo.length < 9) return false;

            var b = false;
            var s = 0;
            var m = 0;
            var multipliers = [3, 7, 1];

            $.each(strNo, function (i, n) {
                if (n == 1 || n == 4 || n == 7) s += (n * 3);
                if (n == 2 || n == 5 || n == 8) s += (n * 7);
                if (n == 3 || n == 6 || n == 9) s += (n * 1);
            });
            b = (s != 0 && s % 10 == 0) ? true : false;

            return b;
        }

Hope this will definitely of help to you.