How jQuery in an array can be searched based on multiple values?

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How jQuery in an array can be searched based on multiple values?
For example, I search by color and os
Thank

JavaScript

var products = [
                     {"id":"1","title":"Apple iPhone 4","os":"ios","color":"red"} 
                     ,{"id":"2","title":"Blac80 Bold","os":"other","color":"blue"} 
                     ,{"id":"12","title":"Black 0","os":"other","color":"red"} 
                     ,{"id":"26","title":"HTC s","os":"android","color":"blue"} 
                     ,{"id":"50","title":"HTC HD7","os":"android","color":"red"} 
                     ,{"id":"21","title":"HTC z","os":"android","color":"blue"} 
                     ,{"id":"11","title":"HTC ion","os":"android","color":"red"} 
                     ,{"id":"3","title":"HTC W","os":"android","color":"blue"} 
                     ,{"id":"6","title":"Motorola","os":"ios","color":"blue"} 
                     ,{"id":"14","title":"Motorola DEFY","os":"ios","color":"red"} 
                     ,{"id":"15","title":"Nokia C7","os":"ios","color":"blue"} 
                     ,{"id":"60","title":"Nokia N8","os":"ios","color":"red"} 
                     ,{"id":"70","title":"Nokia X6","os":"ios","color":"blue"} 
                     ];

Posted 2-Jan-15 3:36am

Member 10418736

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Doug Vanderweide · Answer 1 · 2015-01-02T04:08:00

Solution 1

To get all Nokia N8 in red:

JavaScript

$.grep(products, function(n, i) {
return n.color == "red" && n.os == "Nokia N8";
});

In the anonymous function, n is the item in the array; and i is its index. In other words, Nokia N8 red is actually at index 11, so we could have easily have said:

XML

$.grep(products, function(n, i) {
if(i == 11) {
return true;
}
});

http://api.jquery.com/jquery.grep/[^]

Posted 2-Jan-15 4:08am

Doug Vanderweide

Updated 2-Jan-15 4:09am

v2

Comments

Member 10418736 2-Jan-15 10:55am

I would use this method.
If this was the explanation for this?

var filterdProducts = []; // displayed products array
var key = 0;
filterdProducts = products;
if (a == "android" || i == "ios" || o == "other" || colors == "red") {

if (object.os == a || object.os == i || object.os == o || object.color == colors) {

filterdProducts[key] = object;
key++;
}
}
else {
filterdProducts[key] = object;
key++;
}

Doug Vanderweide 2-Jan-15 12:59pm

The logic you have now won't work.

If what you want is to be able to pass, to a function, arrays of OSes and colors, and get back every match that meets those arrays:

var filterColor = ["red"];
var filterOS = ["android", "ios", "other"];

var filteredProducts = $.grep(products, function(n, i) {
return $.inArray(n.os, filterOS) && $.inArray(n.color, filterColor);
});

filteredProducts is now an array of JSON objects that are red in color, and have an OS of android, ios or other.

Member 10418736 2-Jan-15 14:36pm

Thanks.
All of my code

if (!minPrice && !maxPrice) {
filterdProducts = products;

} else{
$.each(products, function(i, object) {
var curentPrice = parseFloat(object.price);
var priceMinOk = true;
var priceMaxOk = true;
// filter results match the price range
if(maxPrice || minPrice){
if(maxPrice && maxPrice<curentprice){ pricemaxok="false;" }="" if(minprice="" &&="" minprice="">curentPrice){
priceMinOk = false;
}
}
// loop over list and get only related to new array
if (priceMinOk && priceMaxOk) {
a = os.match("android");
i = os.match("ios");
o = os.match("other");
colors = os.match("red");

if (a == "android" || i == "ios" || o == "other" || colors == "red") {

if (object.os == a || object.os == i || object.os == o || object.color == colors) {

filterdProducts[key] = object;
key++;
}
}
else {
filterdProducts[key] = object;
key++;
}
}
});
}

I let the check box to search by color , os

Member 10418736 2-Jan-15 15:00pm

This link is a project
https://www.transferbigfiles.com/0d8678bd-05b1-4a48-98bc-ac53767c0634/-br17aOg-wowmBQ_H2JVBA2
I thank check