Click here to Skip to main content
15,844,364 members
Please Sign up or sign in to vote.
0.00/5 (No votes)
See more:
If I use any file upload control (of Asp or jquery),I want to do this like this way---

I have a webmethod which is called by save button.There is my code for saving data to database.Now I want to acess the uploaded file name in this webmethod so that I can set the path to save in database and then I want the file will be uploaded to server folder.

I have found a code by webhandeller which is good and files are uploading to server folder but I need the file names so that I can save the path in database.

Can anyone help me?

Here's how I do it:
/// <summary>
/// Save an upload into the database.
/// </summary>
/// <param name="fl">Control containing the download.</param>
/// <returns>Status as a string</returns>
private string SaveUpload(FileUpload fl)
    if (fl.HasFile)
            int version = 0;
            string filename = Path.GetFileName(fl.FileName);
            byte[] filedata = fl.FileBytes;
            string strCon = ConnectionStrings.Download;
            using (SqlConnection con = new SqlConnection(strCon))
                // Check version - if the file exists in the DB already, then increase version number.
                using (SqlCommand ver = new SqlCommand("SELECT MAX(version) FROM dlContent WHERE fileName=@FN", con))
                    ver.Parameters.AddWithValue("@FN", filename);
                    object o = ver.ExecuteScalar();
                    if (o != null && o != System.DBNull.Value)
                        // Exists already.
                        version = (int) o + 1;
                // Stick file into database.
                using (SqlCommand ins = new SqlCommand("INSERT INTO dlContent (iD, fileName, description, dataContent, version, uploadedOn) " +
                                                       "VALUES (@ID, @FN, @DS, @DT, @VS, @UD)", con))
                    ins.Parameters.AddWithValue("@ID", Guid.NewGuid());
                    ins.Parameters.AddWithValue("@FN", filename);
                    ins.Parameters.AddWithValue("@DS", "");
                    ins.Parameters.AddWithValue("@DT", filedata);
                    ins.Parameters.AddWithValue("@VS", version);
                    ins.Parameters.AddWithValue("@UD", DateTime.Now);
            return string.Format("{0} uploaded, version = {1}", filename, version);
        catch (Exception ex)
            return "The file could not be uploaded. The following error occured: " + ex.Message;
    return "Please select a file.";

Just call that from your save button and pass the upload control to it.
Share this answer
souvikcode 22-Jan-15 2:11am    
Thanks for your help but please read my question.I want to do it in webmethod.How can I call control like fileupload in a webmethod function?This approach written above is known to me.I want it through webmethod as my save function is in a webmethod.
Done by me using handler by setting url property of uploader.
Share this answer

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

CodeProject, 20 Bay Street, 11th Floor Toronto, Ontario, Canada M5J 2N8 +1 (416) 849-8900