how to done this patterm in c coding

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0 1 2 3 4 5 6 7 8 9
. . . . . * . . . . 
. . . . . . . * . .
. . . . * . . . . .
. . * . . . . . . .

[edit] Code block added[/edit]

Posted 11-Feb-15 19:48pm

Member 11446360

Updated 11-Feb-15 20:19pm

OriginalGriff

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Jeet Gupta 12-Feb-15 2:08am

can you explain your problem little briefly. whats the exact pattern you want

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OriginalGriff · Answer 1 · 2015-02-11T20:26:00

We can't answer this with a generalised solution based on that little information: we have no idea what rules you are using to generate the pattern.

So the only answer we can give you is trivial:

C++

printf("0 1 2 3 4 5 6 7 8 9\n");
printf(". . . . . * . . . .\n");
printf(". . . . . . . * . .\n");
printf(". . . . * . . . . .\n");
printf(". . * . . . . . . .\n");

If you want a generalised sojourn, then you need to consider the rules that govern the generation of the pattern.

KarstenK · Answer 2 · 2015-02-11T20:35:00

better is a solution with some more intelligence.

I wrote some code, I hope it works, but it should show my concept.
- for Loop for line output
- flag array to print stars

C++

for( int i = 0; i < 8; i++)
{
printf("0"+i);
}
printf("\n");

int stars[] = {5,7,4,2};

for(int l = 0; l < 4; l++)//outer loop
{
for(int i = 0; i < 8; i++)//inner loop
{
if( stars[l] == i ) ? printf("*") : printf(" ");
}
printf("\n");
}

how to done this patterm in c coding

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