How to find the salary through date wise

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SQL-Server-2008R2

Hi i have 2 tables ,

VB

EMPID   Name
1       Raghu
2       Venki

and

ID	EMPID 	Hike salary date	Salary
1       1       Jan 1st 2014    1000
2       2       Jan 1st 2014    1200
3       2     March 1st 2014    1300
4       2      june 1st 2014    1200
5       2       SEP 1st 2014    1600

1> Display employee name ,current salary of each employee,with hike date.
2>Display employee name , count of salary increments for each employee.

[edit]Code block added - OriginalGriff[/edit]

Posted 14-Mar-15 1:51am

Raghu425

Updated 14-Mar-15 2:09am

OriginalGriff

v2

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2 solutions

Solution 1

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Posted 14-Mar-15 2:08am

OriginalGriff

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Maciej Los · Accepted Answer · 2015-03-14T03:29:00

Try this:

SQL

-- 1)  Display employee name ,current salary of each employee,with hike date.
SELECT E.EmpName, S2.Salary,  S1.Hike_salary_date
FROM Employees AS E INNER JOIN (
    SELECT EMPID, MAX(Hike_salary_date) AS Hike_salary_date
    FROM Salaries
    GROUP BY EMPID
  ) AS S1 ON E.EMPID = S1.EMPID
INNER JOIN Salaries AS S2 ON E.EMPID = S2.EMPID AND S1.Hike_salary_date = S2.Hike_salary_date


-- 2) Display employee name , count of salary increments for each employee.
SELECT E.EmpName, ROW_NUMBER() OVER(PARTITION BY S.EMPID ORDER BY S.Hike_salary_date) AS IncremCountOfSalary
FROM Employees AS E INNER JOIN Salaries AS S ON E.EMPID = S.EMPID

SQLFiddle[^]