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i seperated red green and blue bits.Thus i have 5 bits of each.then i make it to 8 bit each by shifting them to the left by 3 bits.Then i used the
conversion formula .299*R+.587*G+.114*B .But lost of information is observed.
Is ther is any method to diectly converting it 8 bit grayscale
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How do you expect to preserve data when converting RGB to
grayscale? It's not going to happen.
Mark
Mark Salsbery
Microsoft MVP - Visual C++
![Java | [Coffee]](https://codeproject.global.ssl.fastly.net/script/Forums/Images/coffee.gif)
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Actually i converted 555 RGB to 888 RGB.Then i converted it to grayScale.Is there is any direct method to convert it to grayscale
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Deepu Antony wrote: Is there is any direct method to convert it to grayscale
Not that I know of.
My point was, you're going to lose your RGB data (unless, of course,
you keep it separately).
You stated: "But lost of information is observed"
You can't get the RGB data back once you've converted it.
Mark
Mark Salsbery
Microsoft MVP - Visual C++
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i convert 5 bit Green ,5 bit red ,5 bit blue to each 8 bit (24 bit RGB) by shifting it to left by three bits.while doing this loss of information is observed.I know only to convert 24 bit rgb to gray scale.
is there is any direct method to convert 16 bit RBG to 8 bit gray sale.
Can you help me please
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Deepu Antony wrote: to each 8 bit (24 bit RGB) by shifting it to left by three bits.while doing this loss of information is observed.
There's no loss of information there. You only had 5 bits precision for each color
component to begin with. Widening to 8-bits you still have the same precision.
The image will appear the same on a 16,24,or 32-bitsperpixel display.
Deepu Antony wrote: s there is any direct method to convert 16 bit RBG to 8 bit gray sale.
The only way I know is the usual luminence formula
intensity = 0.2989*red + 0.5870*green + 0.1140*blue It yields an eye-pleasing grayscale representation of an RGB image but
no RGB data is preserved.
Mark
Mark Salsbery
Microsoft MVP - Visual C++
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Hi all,
I have a char buffer and a char*
Lets call it:
char buffer[1024];
char* point;
If I perform a strcpy(), and copy the value of the point into the buffer. If the value of the point changes there after, will the value of the buffer change too??
Many Thanks in advance
Regards,
The only programmers that are better that C programmers are those who code in 1's and 0's ![Green Alien | [Alien]](https://codeproject.global.ssl.fastly.net/script/Forums/Images/alien.gif)
 Programm3r
My Blog: ^_^
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No, because the pointers points to two different locations. Except if you do something like that:
char* point = &buffer[0];
But then of course, you don't need to use strcpy anymore. strcpy just copy bytes from one memory location to another, it is similar as memcpy (except that it works for null-terminated strings).
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Programm3r wrote: If the value of the point changes there after, will the value of the buffer change too??
Why don't you try it and see? 
"A good athlete is the result of a good and worthy opponent." - David Crow
"To have a respect for ourselves guides our morals; to have deference for others governs our manners." - Laurence Sterne
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Hi all,
In my MFC application I've create two buttons, OPEN and CLOSE, used to open a text file and close it. I do it as follows.
<br />
void CSRFToolDlg::OnBnClickedOpen()<br />
{<br />
char* ReadFileName = "G:\\Work On\\CPP\\SRFTool\\text_file.txt" ; <br />
<br />
if(openFile.Open(ReadFileName, CFile::modeCreate | CFile::modeReadWrite))<br />
{<br />
AfxMessageBox("File creates successfully", MB_OK) ;<br />
}<br />
else<br />
{<br />
AfxMessageBox("Error in file opening", MB_OK) ;<br />
}<br />
}<br />
<br />
<br />
void CSRFToolDlg::OnBnClickedClose()<br />
{<br />
openFile.Close() ;<br />
}<br />
What I want to do is, until user click the Open button the Close button should be disable. How should I do it. Those stuff really new for me.
Thanks
-- modified at 6:08 Thursday 11th October, 2007
I appreciate your help all the time...
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Stablish a control member variable to the with the class assistant (ctrl + w, second propertie page) or
use CWindow::GetDlgControl (nID) in order to have access.
Then use EnableWindow (TRUE); //or false as you want
Greetings.
--------
M.D.V.
If something has a solution... Why do we have to worry about?. If it has no solution... For what reason do we have to worry about?
Help me to understand what I'm saying, and I'll explain it better to you
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Can you explain it with my code. What you mean second property page. I'm unable to found that.
I appreciate your help all the time...
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hi,
Try this one...
Disable the button in OnInitDialog of your dialog class
eg:
GetDlgItem(UR_CLOSE_BUTTON_ID)->EnableWindow(FALSE);
Enable that button in OnBnClickedOpen function
void CSRFToolDlg::OnBnClickedOpen()
{
char* ReadFileName = "G:\\Work On\\CPP\\SRFTool\\text_file.txt" ;
if(openFile.Open(ReadFileName, CFile::modeCreate | CFile::modeReadWrite))
{
AfxMessageBox("File creates successfully", MB_OK) ;
GetDlgItem(UR_CLOSE_BUTTON_ID)->EnableWindow(TRUE);
}
else
{
AfxMessageBox("Error in file opening", MB_OK) ;
}
}
Again Disable the button in OnBtnClickedClose()
void CSRFToolDlg::OnBnClickedClose()
{
openFile.Close() ;
GetDlgItem(UR_CLOSE_BUTTON_ID)->EnableWindow(FALSE);
}
If you the control variable of Close button, the user that variable in place of GetDlgItem(UR_CLOSE_BUTTON_ID)
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Lakshmi_p wrote: If you the control variable of Close button, the user that variable in place of GetDlgItem(UR_CLOSE_BUTTON_ID)
Do you mean that the ID of the control(button ID). I'll do it in that way, it's disable after clicking the Open button.
If I can load
GetDlgItem(UR_CLOSE_BUTTON_ID)->EnableWindow(FALSE);
in form load, it will work. How to access to the form load.
I appreciate your help all the time...
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form load function you can find it in visual basic.
but in vc++6.0, the analogous function is init dialog.
you can write the code as suggested by lakshmi there.
and also in the buttons.
any more doubts?
get back.
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Actually I found a way to do it. Just define in OnInitDialog(). It works. What you think about that.
I appreciate your help all the time...
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congradulations!
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Thanks. Seems to me lots of things can be done there, like global initializations and stuff. I want to try them later.
I appreciate your help all the time...
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mmm, ok, let see...
You stablish your form or your dialog in the resource editor, then you drag a button from the toolbar and drop it on your form. If you select the button and press enter, you get a properties window where as default comes IDC_BUTTON1 this is the ID of the button (you may always change it to you names, i.e. IDC_BUTTON_OPEN), you have the caption and so on...
once you have the buttons with the correct names, you can press CTRL + W and comes the class wizard assistant. When it opens you have the "Message order table" property sheet opened, the second is "Member variables", the third "Automation" and so on...
In the second one "Member variables" you will have a list with all the IDs of the form, in this case the two buttons, click on add variable and complete the "m_ " field with a name to reference the button in your code.
Create the second button and uncheck the property "Enabled" in the properties window of the button (at the bottom)
If you do it in that way, you can always use this name directly to access or modify the button.
You will have something like that in your CDialog.cpp
void CMyView::DoDataExchange(CDataExchange* pDX)
{
CFormView::DoDataExchange(pDX);
DDX_Control(pDX, IDC_BUTTON_OPEN, m_cbOpen);
DDX_Control(pDX, IDC_BUTTON_CLOSE, m_cbClose);
}
one that is done...
you can use another time the class assistant (this time in the first sheet "Messages Table") to look for the name of your button in the left listbox and include a function of the right listbox. In this case your OnButtonOpenClick
void CMyView::OnButtonOpenClick()
{
m_cbClose.EnableWindow (TRUE);
}
and to reset the enable
void CMyView::OnButtonCloseClick()
{
m_cbClose.EnableWindow (FALSE);
}
The other way to make it is without using member variables, taking a pointer to the control using the ID and the GetDlgControl () function as the other answer already explains.
Greetings.
--------
M.D.V.
If something has a solution... Why do we have to worry about?. If it has no solution... For what reason do we have to worry about?
Help me to understand what I'm saying, and I'll explain it better to you
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Thank you for the long explanation. I learn a lot from there. Meantime I found one way to do it. As I asked earlier, I'm looking to find where the form load or any smiler operation is going on.
OnInitDialog() behave like that. I placed the code
GetDlgItem(IDC_CLOSE)->EnableWindow(FALSE) ;
for Close button it works. What's your comments.
Thanks 
I appreciate your help all the time...
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if it works... it works. 
Greetings.
--------
M.D.V.
If something has a solution... Why do we have to worry about?. If it has no solution... For what reason do we have to worry about?
Help me to understand what I'm saying, and I'll explain it better to you
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Ya, seems to me it is correct. But haven't found that it is used on the web, not on the MSDN as well. Anyway it works as form load in Visual Studio .Net 2003 
I appreciate your help all the time...
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use of m_Open.EnableWindow(1);or 0 for disable
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I created an MFC ActiveX Control with VC++ Wizard. Compiled it without changing anything. Created a webpage, put it in (it draws an ellipse).Now drag the horz scrollbar, the image inside the activeX control is teared and dragged terribly. It even draws the border on the surface of activeX control. how to avoid this flickering.
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