C / C++ / MFC

PJ Arends31-May-05 23:01

PJ Arends

31-May-05 23:01

Show your code.

"You're obviously a superstar." - Christian Graus about me - 12 Feb '03

"Obviously ??? You're definitely a superstar!!!" mYkel - 21 Jun '04

Within you lies the power for good - Use it!

Honoured as one of The Most Helpful Members of 2004

Nilesh K.31-May-05 23:14

Nilesh K.

31-May-05 23:14

<br />
        CreateBitmap();<br />
<br />
	m_pMemDC = new CDC;<br />
<br />
	VERIFY( m_pMemDC->CreateCompatibleDC(m_pWinDC) );<br />
<br />
	m_pOldBitmap = m_pMemDC->SelectObject( &m_Bitmap );<br />
<br />
	CString str("This is a test message");<br />
<br />
	CPen cp;<br />
	cp.CreatePen(PS_SOLID, 2,RGB(255,255,255));<br />
<br />
	CRect rect;<br />
	GetClientRect(&rect);<br />
<br />
	m_pMemDC->SelectObject(&cp);<br />
	m_pMemDC->DrawText(str,str.GetLength(),rect,DT_LEFT);<br />
<br />
	PBITMAPINFO pbi = getInfoStruct(m_Bitmap);<br />
<br />
	CreateBMPFile("test.bmp",pbi,m_Bitmap,m_pMemDC->m_hDC);<br />
        m_pMemDC->SelectObject(m_pOldBitmap);<br />

<bold>- Nilesh
<italics>
"Reading made Don Quixote a gentleman. Believing what he read made him mad" -George Bernard Shaw

ThatsAlok1-Jun-05 0:15

ThatsAlok

1-Jun-05 0:15

Nilesh K. wrote:
CreateBMPFile("test.bmp",pbi,m_Bitmap,m_pMemDC->m_hDC);

I Believe, Such function doesn't exist in WIndow's Api!.
could you show coding for that too, as your problem may be at the time of saving!

"Opinions are neither right nor wrong. I cannot change your opinion. I can, however, change what influences your opinion." - David Crow

cheers,
Alok Gupta

Nilesh K.1-Jun-05 0:23

Nilesh K.

1-Jun-05 0:23

<br />
CRect rect;<br />
	CSize size;<br />
<br />
	GetClientRect(&rect);<br />
	size = rect.Size();<br />
<br />
	LPBITMAPINFO lpbi;<br />
<br />
	// Fill in the BITMAPINFOHEADER<br />
	lpbi = (LPBITMAPINFO) new BYTE[sizeof(BITMAPINFOHEADER) + (256 * sizeof(RGBQUAD))];<br />
	lpbi->bmiHeader.biSize = sizeof(BITMAPINFOHEADER);<br />
	lpbi->bmiHeader.biWidth = size.cx;<br />
	lpbi->bmiHeader.biHeight = size.cy;<br />
	lpbi->bmiHeader.biPlanes = 1;<br />
	lpbi->bmiHeader.biBitCount = 8;<br />
	lpbi->bmiHeader.biCompression = BI_RGB;<br />
	lpbi->bmiHeader.biSizeImage = WIDTHBYTES((DWORD)size.cx * 8) * size.cy;<br />
	lpbi->bmiHeader.biXPelsPerMeter = 0;<br />
	lpbi->bmiHeader.biYPelsPerMeter = 0;<br />
	lpbi->bmiHeader.biClrUsed = 0;<br />
	lpbi->bmiHeader.biClrImportant = 0;<br />
<br />
	// Fill in the color table<br />
	UINT uUsage = DIB_RGB_COLORS;<br />
<br />
	memcpy( lpbi->bmiColors, m_rgbPalette, sizeof(RGBQUAD) * 256 );<br />
<br />
	m_pWinDC = new CWindowDC(this);<br />
<br />
	HBITMAP hBitmap = CreateDIBSection( m_pWinDC->m_hDC, lpbi, uUsage, (void **)&m_pBits, NULL, 0 );<br />
<br />
	delete [] (BYTE *)lpbi;<br />
<br />
	ASSERT(hBitmap != NULL);<br />
<br />
	m_Bitmap.Attach( hBitmap );<br />

<bold>- Nilesh
<italics>
"Reading made Don Quixote a gentleman. Believing what he read made him mad" -George Bernard Shaw

How can I disable Firewall

khan++1-Jun-05 1:38

khan++

1-Jun-05 1:38

CPen cp;
cp.CreatePen(PS_SOLID, 2,RGB(255,255,255));

Why write white text?

Maybe the color of the bitmap is white: RGB(255,255,255), that is why the text does not show.

this is this.

Ali_quaidian31-May-05 21:42

Ali_quaidian

31-May-05 21:42

I need to disable firewalls. If all firewall cannot be disable then at least guide me to disable WindowsXp firewall.

I am using Visual C++ 6.0

Thanks

Quaidian For Once, Quaidian For Ever

Re: How can I disable Firewall

Christian Graus31-May-05 22:01

Christian Graus

31-May-05 22:01

The firewall is unlikely to shut down quietly - you should just tell your user to turn it off, assuming you absolutely have to.

Christian Graus - Microsoft MVP - C++

transfer data between dialog boxes

abhi_code31-May-05 21:36

abhi_code

31-May-05 21:36

Hi ALL !

actually i have a main dialog which has 3 buttons
the first button when clicked dispplays a dialog
with 3 radio buttons. iam selecting one of radio
button say r1.
the second button when clicked displays another
child dialog with 2 radio buttons. out of which iam
selecting one of radio button say R1.
Now when i press the view properties that is third
button i should get the information from these
selected radio buttons that is r1 and R1 and get it
displayed in new dialog box.
iam able to display third dialog box , but
unable to retrieve info from the 2 radio buttons which
are in 2 dialog boxes.
now the problem is how to retrieve
information from the 2 dialogs and display it in the
third dialog.

So Reply me as soon as possible

Thanks in Advance,

Abhijeet Jadhav

Cedric Moonen31-May-05 21:55

Cedric Moonen

31-May-05 21:55

The best way to do that is something like that:

Say your main dialog is CMainDlg, and your three other dialogs are CDialog1, CDialog2 and CDialog3

void CMainDlg::OnButton1()<br />
{<br />
   CDialog1 Dlg;<br />
   Dlg.DoModal();<br />
<br />
   RadioStatus1 = Dlg.GetRadioStatus();<br />

The same thing for Button2 (retrieving RadioStatus2 from CDialog2

void CMainDlg::OnButton3()<br />
{<br />
   CDialog3 Dlg;<br />
   Dlg.SetRadioStatus(RadioStatus1, RadioStatus2);<br />
   Dlg.DoModal();<br />
}

So, a quick explanation: RadioStatus1 and RadioStatus2 are member variables from your main dialog that will hold the status of the two radio buttons. In the CDialog1 and CDialog2 classes, you must add a handler function for the OnOk event (or when the dialog closes) to retrieve the status of the radio button and save it in a member variable of this class. Then add the member function GetRadioStatus that will return this value.

Finally, for the third dialog, you must add a function that will send the values of the buttons to this dialog before calling DoModal.

Ok, this is just an example of how to do it. Hope this is clear enough...

abhi_code1-Jun-05 0:59

abhi_code

1-Jun-05 0:59

Thanks a lot cedric ...for this information
this solves my problem...in case of any doubt, i will ask you later....

Abhijeet Jadhav

Christian Graus31-May-05 21:58

Christian Graus

31-May-05 21:58

abhi_code wrote:
So Reply me as soon as possible

How unusual, someone in a hurry....

You pass the values on to the third dialog, and expose them in the second dialog using a get method, and variables that you set in the dialog class in the OnClose method, as the radio buttons won't exist once the dialog is closed.

Christian Graus - Microsoft MVP - C++

abhi_code1-Jun-05 1:02

abhi_code

1-Jun-05 1:02

Thanks Christian for the information

Abhijeet Jadhav

Assignement operator

Haakon S.31-May-05 21:17

31-May-05 21:17

I have a little problem with the assignement operator and inheritance. How does this work:

class CBaseClass{
int m_intB;
const CBaseClass& operator=(const CBaseCase& b);
}

class CDerivedClass : public CBaseClass{
int m_intD;
const CDerivedClass& operator=(const CDerivedClass& d);
}

Both assignement operators are defined like this

const CBaseClass& CBaseClass::operator=(const CBaseClass& b){
m_intB=b.m_intB;
return *this;
}

Subsequently

CDerivedClass* a_obj=new CDerivedClass;
a_obj.m_intB=5;
a_obj.m_intD=6;

CDerivedClass* b_obj=new CDerivedClass;

If I do

*b_obj=*a_obj;

only the CBaseClass member is assigned.

Is it possible to make the assignement operator virtual?

Regards, Haakon S.

A sure cure for seasickness is to sit under a tree.
Spike Milligan

Haakon S.31-May-05 21:20

31-May-05 21:20

Oops, a small error.

The statements:

a_obj.m_intB=5;
a_obj.m_intD=6;

shall of course be:

a_obj->m_intB=5;
a_obj->m_intD=6;

Haakon S.

A sure cure for seasickness is to sit under a tree.
Spike Milligan

PJ Arends31-May-05 21:50

PJ Arends

31-May-05 21:50

Haakon S. wrote:
only the CBaseClass member is assigned

I would have thought only the CDerivedClass member would be assigned Confused | :confused:

What I would do is call the base class operator= from the derived class operator= to assign the base class members

const CDerivedClass& CDerivedClass::operator =(const CDerivedClass &d)
{
   *(CBaseClass *)this = (CBaseClass &)d;   // calls CBaseClass::operator =
   m_intD = d.m_intD;
   return *this;
}

"You're obviously a superstar." - Christian Graus about me - 12 Feb '03

"Obviously ??? You're definitely a superstar!!!" mYkel - 21 Jun '04

Within you lies the power for good - Use it!

Honoured as one of The Most Helpful Members of 2004

Haakon S.1-Jun-05 3:50

1-Jun-05 3:50

PJ Arends wrote:
I would have thought only the CDerivedClass member would be assigned

No, actually this assignes values for the base class:

*b_obj=*a_obj;

To assign values for the derived class I have to write:

*(CDerivedClass*)b_obj=*(CDerivedClass*)a_obj;

This is what is puzzling me. This is happening even if the type is CDerivedClass for both objects Confused | :confused:

Regards, Haakon.

A sure cure for seasickness is to sit under a tree.
Spike Milligan

PJ Arends1-Jun-05 14:57

PJ Arends

1-Jun-05 14:57

That is truely wierd Confused | :confused:

You have to type cast a CDerivedClass pointer to a CDerivedClass pointer to call a CDerivedClass member function?!?

There is obviously something else going on that you have not posted here. Have you tried doing a "Rebuild All"?

"You're obviously a superstar." - Christian Graus about me - 12 Feb '03

"Obviously ??? You're definitely a superstar!!!" mYkel - 21 Jun '04

Within you lies the power for good - Use it!

Honoured as one of The Most Helpful Members of 2004

Haakon S.1-Jun-05 20:54

1-Jun-05 20:54

PJ Arends wrote:
Have you tried doing a "Rebuild All"?

Oh, yes. I have rebuilt many times, and the behaviour is definitively as described.

This is confusing, and I can't find any documentation about it. Which is frustrating.

Regards, Haakon S.

A sure cure for seasickness is to sit under a tree.
Spike Milligan

Haakon S.2-Jun-05 0:00

2-Jun-05 0:00

Sorry, got it now.

The pointers are declared as CBaseClass pointers initially, but I've tried to cast them to CDerivedClass pointers permanently. That appears to have failed. Then it makes sence:

*pBaseB=*pBaseA;

will assign values for base class, where:

*(CDerivedClass*)pBaseB=*(CDerivedClass*)pBaseA;

will assign values for the derived class.

Regards, Haakon S.