If a listview item is doubled clicked, help.

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C#

private void listView1_MouseDoubleClick(object sender, MouseEventArgs e) { if (listView1.Items[12].Selected) { MessageBox.Show("Test"); } }

The above code works perfectly! But when I use my search box, it removes the ones that do not contain related text. So the indexes change, so item 12 is now, say, item 3. This is a problem. How can I fix this, thanks.

Posted 7-Nov-12 10:11am

Member 8195177

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fjdiewornncalwe · Answer 1 · 2012-11-08T10:23:00

Solution 2

If you know the text that should be selected in the listview then you don't need to know the index at all. Just check the selected item's text.

C#

if( listview1.SelectedText == "YourStaticValue" )
{
   MessageBox.Show("Test");
}

Posted 8-Nov-12 10:23am

fjdiewornncalwe

Comments

ExcelledProducts 8-Nov-12 16:30pm

Yes but the text is not always the same so you need to find the index.

fjdiewornncalwe 8-Nov-12 16:34pm

I disagree. The OP is always looking for the same item that moves around and changes index. Therefore the text he's searching for is static.

ExcelledProducts 8-Nov-12 16:42pm

That very well be true but with different users and different databases their are different text values so you must calculate the new index.

fjdiewornncalwe 8-Nov-12 16:43pm

Agreed. That is why I called it YourStaticValue, not YourConstantValue.

ExcelledProducts 8-Nov-12 16:47pm

But the static value may change between users.

fjdiewornncalwe 8-Nov-12 16:52pm

Static doesn't imply that the value remains the same. Static in this case means "Whatever option you are looking for" as opposed to the "I absolutely want the item at index 12"

ExcelledProducts 8-Nov-12 17:28pm

But what if the text of the index 12 changes?

Ritwesh 9-Nov-12 11:36am

A string variable declared in the class can be used. This variable can be used to store the text in the search box. So the code can be :

if(listview1.SelectedText.equals(str))
{
//required code
}

Won't this work?

ExcelledProducts 9-Nov-12 15:50pm

This will work only if the text is always the same.

ExcelledProducts · Answer 2 · 2012-11-07T11:01:00

I am not very familiar with C# but i think you could interpret this VB.NET Code. You need to do some math to figure out the difference between the two index's

VB

Public OldIndex As String
Public NewIndex As String
Public FinalIndex As String
Public ItemNumber As Integer

Know you only need to calculate the new index when you search it. So when you search it put this in your code.

VB

OldIndex=ListView1.Index
'Your search code
'After you search you get a new index so get the new one
NewIndex=ListView1.Index
'if the value is a negative number then the index is higher, if it is a positive number then the index is lower.
FinalIndex=NewIndex-OldIndex

If FinalIndex < 0 Then
FinalIndex=FinalIndex*-1
ItemNumber=12 + FinalIndex
ElseIf FinalIndex > 0 Then
FinalIndex= 12 - FinalIndex
End If

Their you go you should replace your code with this in the listView1_MouseDoubleClick

C#

private void listView1_MouseDoubleClick(object sender, MouseEventArgs e)
        {
            if (listView1.Items[ItemNumber].Selected)
            {
                MessageBox.Show("Test");
            }
        }

Hope this helps if it does not please don't complain, I tried my best :)

Member 8195177 · Answer 3 · 2012-11-19T16:36:00

I figured it out. This worked well for my purposes.

C#

private void listView1_DoubleClick(object sender, EventArgs e)
{
         ListViewItem people = listView1.FindItemWithText("Joe");
         ListViewItem cars = listView1.FindItemWithText("Toyota");
 
      if (people != null && listView1.FindItemWithText("Joe").Selected)
      {
      // Code here etc....
         Form1 form1 = new Form1();
         form1.Show();
         this.hide();
      }
      if (cars != null && listView1.FindItemWithText("Toyota").Selected)
      {
         // Code here etc....
         MessageBox.Show("Text");
      }
}

If a listview item is doubled clicked, help.

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