How to Convert 3D arrays to 1d arrays

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1.00/5 (1 vote)

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How to convert 3D arrays to 1D arrays ?
for example i want to Edit arr[i][j][k]; but i don't want addressing array with this way.
in fact i want to give one number (instead 3 number ) to program for access the element of array.
(How to Save 3d array to 1d array???!!!)
please help me.

Posted 26-Oct-12 7:57am

meysamp73

Updated 26-Oct-12 8:16am

v4

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OriginalGriff 26-Oct-12 13:58pm

This is not a good question - we cannot work out from that little what you are trying to do.
Remember that we can't see your screen, access your HDD, or read your mind.
Use the "Improve question" widget to edit your question and provide better information.

meysamp73 26-Oct-12 14:15pm

Please help me
thanks

Sergey Alexandrovich Kryukov 26-Oct-12 15:06pm

I think I understand what's the problem -- please see my answer.
--SA

meysamp73 26-Oct-12 14:21pm

hey
help me

Sandeep Mewara 26-Oct-12 14:42pm

Your question is still not clear even though you have updated it.

Rephrase it.

Sergey Alexandrovich Kryukov 26-Oct-12 15:06pm

I think I understand what's the problem -- please see my answer.
--SA

Sergey Alexandrovich Kryukov 26-Oct-12 15:09pm

To OP: please don't post irrelevant statements, especially as "solutions". They will be removed, no one gets notifications...
--SA

3 solutions

Solution 3

hi,
suppose your 3d arr[i][j][k] array has integers then declare another 1d array of size i*j*k and use nested loops to read each element in the 3d array and assign them to the 1d array.

for more about nested loops :

http://www.tutorialspoint.com/cplusplus/cpp_nested_loops.htm[^]

hope this helps

Posted 26-Oct-12 9:16am

chandanadhikari

Updated 26-Oct-12 9:20am

v3

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Sergey Alexandrovich Kryukov · Accepted Answer · 2012-10-26T09:06:00

Solution 2

Multidimensional arrays are just an abstraction for programmers. They have the same structure as single-dimensional arrays with the same total number of elements. All you need is understanding of the order of the indices in the multidimensional syntax: the elements are consider arranged sequentially in the following way: the change in rightmost index by one points to the nearest element in memory.

Please see:
http://www.osdata.com/programming/arrays/arrays.html[^],
http://www.cplusplus.com/doc/tutorial/arrays/[^], section "Multidimensional arrays".

So, all you need it to understand how array elements addressed by multiple indices are arranged in memory, and that all indices are zero-based. It's all about understanding of indexing and syntax, nothing else.

For example, having

C++

int arr[4][6][12];

these addressings are equivalent:

C++

bool sameThing = arr[1][1][0] == arr[24]; // true; 6 * 4
sameThing = arr[1][1][1] == arr[25]; // true
// and so on...

—SA

Posted 26-Oct-12 9:06am

Sergey Alexandrovich Kryukov

Updated 2-Nov-12 11:25am

v4

Comments

pasztorpisti 28-Oct-12 22:09pm

+5 to counter vote. The OP wanted a ready made solution, he isn't really interested in whats going on behind the curtains... I think you made a mistake here: arr[3][5][0] with linear indexing is 3*6*12 + 5*12 + 0 but this isn't a reason for a 1.

Sergey Alexandrovich Kryukov 28-Oct-12 23:08pm

Thank you.
No, the reason for 1 is likely a very different: I fount some 10 1's in a row -- it looks more like personal hatred. Funny. The error..? well, I'll check up, thank you.
--SA

pasztorpisti 29-Oct-12 6:05am

I know what you are talking about and really don't know what these people want to achieve with this. They are just wasting their time.

Sergey Alexandrovich Kryukov 29-Oct-12 10:59am

(Sigh...) You are right, but there is nothing wrong in addressing the same object with arrays of different rank; and the skill of doing such things is important. If some programming "trick" is possible but using makes no sense, I usually don't provide such solution but try to explain why it's useless. This question is not exactly the case. Good point about wasted time though -- and it's up to you how to spend it, but I would not recommend address anything which makes no sense.
--SA

pasztorpisti 29-Oct-12 11:16am

Sorry, I think my previous post was confusing, I meant the downvoters waste their time. Knowing how array indexing works is useful. This is again just about getting to know an anti-pattern that is always useful. :-) It might come handy if you implement a custom datastructure.

Sergey Alexandrovich Kryukov 29-Oct-12 12:49pm

That is true, too... :-)
--SA

Eugen Podsypalnikov · Accepted Answer · 2012-10-26T09:27:00

Please take a look at the last function below :) :

C++

#define IS_IDX_VALID(i, count) (0 <= i && i < count)

class CTest
{
  enum { slotCount = 10, rowCount = 10, colCount = 20, invalidValue = INT_MIN };

  int m_arValues[slotCount][rowCount][colCount];

  void InitValues() {..}

public:
  CTest() { InitValues(); }

  int GetValue(int s, int r, int c) const
  {
    int iResult(invalidValue);

    bool bValidParams(IS_IDX_VALID(s, slotCount) &&
                      IS_IDX_VALID(r, rowCount) &&
                      IS_IDX_VALID(c, colCount) &&);
    ASSERT(bValidParams);

    if (bValidParams) {
      iResult = m_arValues[s][r][c];
    }

    return iResult;
  }

  int GetValue(int iAbsAddr) const
  {
    int iResult(invalidValue);

    static int siSlotMaxCount(rowCount * colCount)
    static int siAbsMax(slotCount * siSlotMaxCount);
    ASSERT(IS_IDX_VALID(iAbsAddr, siAbsCount));

    if (IS_IDX_VALID(iAbsAddr, siAbsCount)) {
      int s = iAbsAddr / siSlotMaxCount,
          t = iAbsAddr % siSlotMaxCount,
          r = t / colCount,
          c = t % colCount;

      iResult = m_arValues[s][r][c];
    }    

    return iResult;
  }
};