Get a double by dividing two int

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this may seemed very basic...almost ashamed to asked.

But I want to get a double by dividing an integer by another integer.

I want to 0.8 by doing this

but I notice it is not returning the 4/5 only whole numbers.

What I have tried:

double score;
             score = 4/5*100;

Posted 1-Mar-17 15:59pm

Member 9331278

Updated 1-Mar-17 16:19pm

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PIEBALDconsult 1-Mar-17 23:07pm

score = 4*100.0/5;

2 solutions

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Karthik_Mahalingam · Answer 1 · 2017-03-01T16:10:00

Solution 1

double score = (double)4 / (double)5 * 100;

Posted 1-Mar-17 16:10pm

Karthik_Mahalingam

Bryian Tan · Answer 2 · 2017-03-01T16:19:00

Solution 2

This should work too

C#

double score= (double)4/5 * 100;

Posted 1-Mar-17 16:19pm

Bryian Tan

Comments

Karthik_Mahalingam 1-Mar-17 22:27pm

Yes :)

Member 9331278 1-Mar-17 22:34pm

int total;
int num = Convert.ToInt32(txtScore.Text);
if (ViewState["total"] == null)
{
total = num;
}
else
{
total = (int)ViewState["total"] + num;
}
ViewState["total"] = total;

int count;

if (ViewState["count"] == null)
{
count = 1;
}
else
{
count = (int)ViewState["count"] + 1;
}
ViewState["count"] = count;

double score = double((total) / double(count *5)) * 100;
//not working

// score
Label1.Text = total.ToString() + " count " + count.ToString() + " Score " + score.ToString();

Karthik_Mahalingam 1-Mar-17 22:37pm

what is the value you are getting in score

Member 9331278 1-Mar-17 22:39pm

0

Member 9331278 1-Mar-17 22:40pm

0 unless its a whole number

Karthik_Mahalingam 1-Mar-17 22:50pm

value of total and count ?

Bryian Tan 1-Mar-17 23:00pm

what if you use these syntax

double score = (double)total /(count * 5) * 100; OR
double score = (double)total / (double)(count * 5) * 100;