Variable dynamic initialisation

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Code that assigns some value to variable y and prints on console, would want the code to reassign value and print

public class Ifelse
{
    public static void main(String[] args) throws IOException
    {     
     String d = null ;      
     BufferedReader reader = new BufferedReader(new InputStreamReader(System.in)); 
     System.out.print("A:" ); 
     String y = reader.readLine();
     System.out.print("You entered: " + y);
     String Word = reader.readLine();   
     System.out.print("A:" );
     String y = reader.readLine(); 
     System.out.print("NowAis: " + z);
    }
}

the code says variable y is already defined, would want to reassign value to y

regards

What I have tried:

changed code and searched java classes

Posted 13-May-18 5:38am

four systems

Updated 13-May-18 5:52am

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Richard MacCutchan 13-May-18 12:08pm

This is much the same as your previous question where you seem to be using random variables without really understanding their lifetime. I would strongly suggest you go to The Java™ Tutorials[^] and learn the basics. And using meaningful names for your variables instead of a,y and z will help to make things clearer.

four systems 13-May-18 12:22pm

t

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OriginalGriff · Accepted Answer · 2018-05-13T05:54:00

And so it is. You can't create two variables with the same name in the same scope: the system wouldn't know which one you meant to use!

public static void main(String[] args) throws IOException
{
 String d = null ;
 BufferedReader reader = new BufferedReader(new InputStreamReader(System.in));
 System.out.print("A:" );
 String y = reader.readLine();
 System.out.print("You entered: " + y);
 String Word = reader.readLine();
 System.out.print("A:" );
 y = reader.readLine();
 System.out.print("NowAis: " + y);
}

Should fix it.