Click here to Skip to main content
15,904,652 members
Please Sign up or sign in to vote.
0.00/5 (No votes)
See more:
Dim postUrl
postUrl = "http://localhost:8002/XXX.asmx/methodname"
Set xmlhttp = server.Createobject("Microsoft.XMLHTTP")
xmlhttp.Open "POST",postUrl,false
xmlhttp.setRequestHeader "Content-Type","application/x-www-form-urlencoded"
xmlhttp.send DataToSend
Response.Write DataToSend & "<br>"
Posted

1 solution

I guess so. Looks like a XMLHttpRequest using a POST method. This should work.

Facing any issues?
 
Share this answer
 

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)



CodeProject, 20 Bay Street, 11th Floor Toronto, Ontario, Canada M5J 2N8 +1 (416) 849-8900