How to validate length and match required character

Question

4.00/5 (1 vote)

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This how i validate my required characters and the length

JavaScript

JavaScript

function submitChangej(){

  var firstname = /^[a-zA-Z-\s]{2,128}$/;
  var lastname = /^[a-zA-Z-\s]{2,128}$/;
 
  
  var inputlastName = document.getElementById("lastname"); 
  var inputfirstName = document.getElementById("firstname");
 
  
 var inputSubmit = document.getElementById("apply");
  
 var Container = document.getElementById('Agreement');
  //if((firstname.value.match(firstname)) || (lastname.value.match(lastname))
  if((inputfirstName.value.length < 2 || inputfirstName.value.length > 128 ) || ( inputlastName.value.length < 2 || inputlastName > 128 )){
 
 	
		Container.style.display = 'none';
  }
  else{
	  
        Container.style.display = 'block';
  }
  
}

</script>

I want to hide the button if value does not match the required type, I m able to hide it on the length, but my match does not work.

I than call my method

JavaScript

submitChangej()

on the fields that i validate.

I have commented other code, that didn't work the match one.

Your will be appreciated

Posted 3-Dec-15 21:47pm

iDoKin

Updated 3-Dec-15 21:48pm

v2

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yeleswarapu ramakrishna 4-Dec-15 4:30am

did you get the solution the code mentioned below by me is working for me so i hope it works for u as well

2 solutions

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phil.o · Accepted Answer · 2015-12-03T22:07:00

Solution 1

I think your problem is that you are using the same name for your regular expression variables, and for your controls.

Have you tried to give both these groups different naming schemes?

Posted 3-Dec-15 22:07pm

phil.o

Comments

iDoKin 4-Dec-15 4:19am

Yes, i changed them to regLastname and regFirsname

phil.o 4-Dec-15 4:31am

No you didn't. In the statement document.getElementById("lastname"), apparently you still have some controls that have the same name as your variables. You should not :)

iDoKin 4-Dec-15 5:50am

I will try different name, and see what i get.

yeleswarapu ramakrishna · Accepted Answer · 2015-12-03T22:20:00

Solution 3

Posted 3-Dec-15 22:20pm

yeleswarapu ramakrishna

Updated 6-Dec-15 23:01pm

v5

Comments

iDoKin 4-Dec-15 5:50am

This does not seem to be working.

yeleswarapu ramakrishna 4-Dec-15 6:39am

you said in your question match is not working in the above mentioned code the match is working

iDoKin 7-Dec-15 3:31am

I don't want to hard-code the name like you did in var inputlastName = "ramakrishna";

yeleswarapu ramakrishna 7-Dec-15 4:04am

i was just giving example of how to do it and the hard-code part do it yourself and don't complain of simple things cause you are not my employer

iDoKin 7-Dec-15 4:09am

No I was not complaining, but thanks.

yeleswarapu ramakrishna 7-Dec-15 4:18am

always welcome buddy.i have removed hard-code since you did'nt want it

iDoKin 7-Dec-15 5:08am

I made it work. Thanks hey.

yeleswarapu ramakrishna 7-Dec-15 5:28am

happy to know you solved it.happy coding

iDoKin 7-Dec-15 6:27am

How can i not allow space as first character in those fields?

iDoKin 7-Dec-15 6:30am

Space must only be between the words, currently i can be able to not accept space only as character when you submit. But the problem is when your enter first letter as a space, i don't want that. Space should be between the words only.

yeleswarapu ramakrishna 7-Dec-15 6:33am

You can use myString.substring(0,1) or myString[0] to get the first character.

You can trim the input; this doesn't check whether or not it starts with a space, it makes such a check redundant and gives you usable input regardless of whether or not the original string had an initial space.

You could also match the string for /^\s/ which means an initial whitespace, or /^\s+/ meaning any number of initial whitespace.

iDoKin 7-Dec-15 6:36am

So i will have var firstname = /^[a-zA-Z-/^\s+/]{2,128}$/g; ?

iDoKin 7-Dec-15 6:44am

But this gave me error

yeleswarapu ramakrishna 7-Dec-15 6:45am

i think u better use trim in javascript on blur and assign the value gain to the firstname field

yeleswarapu ramakrishna 7-Dec-15 6:44am

it's my office time i am already late so i will answer after i get back that is 11 hours from now sorry if its urgent.

iDoKin 7-Dec-15 6:45am

No problem.

iDoKin 7-Dec-15 8:13am

/^[a-zA-Z][a-zA-Z\s]{2,128}$/ solved my issue.

yeleswarapu ramakrishna 8-Dec-15 1:00am

good

iDoKin 8-Dec-15 3:14am

Thanks for your time