Validate Name using DataTable Column Values

Question

2.00/5 (2 votes)

See more:

I have a table with a column named 'InvalidCharacters', around 100 rows in the table,in the sense 100 invalid characters,I have to validate a string[username],
against these 100 characters, if any of the character in the string matches the invalid characters in the table, the string is considered to be invalid.

I am looking for LINQ sort of code, instead of for/foreach loops

I am supposed to perform validation on server side, no client side script please

any suggestion is appreciated

Posted 20-Nov-12 22:28pm

PBGuy

Add a Solution

4 solutions

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

Greysontyrus · Answer 1 · 2012-11-21T00:44:00

Not sure why you need to have 100 rows. 1 string will do as you can convert that to an array of chars in the code, but I'm sure you must have a reason ;)

/Edit: This assumes you use .Net4.0 and above

C#

char[] invalidCharacters = @"!@'#,.$%_/\".ToArray();
string textToTest = "foo@bar";

bool isValid = textToTest.ToArray()
               .Join(invalidCharacters,
                     ttt=>ttt,
                     ic=>ic,
                     (ttt,ic)=>ttt)
               .Any();

I have used an invalid char string but I hope you can see how you could use your table instead. You could use this query to return a list of the invalid chars used also, just knock off the Any().

Let me know via comment if you need any more on this ^_^

ManojDhobale · Answer 2 · 2012-11-21T01:38:00

I think this will help u

public bool IsValidString(string stringToCheck)
   {
       bool IsValidString = true;
       foreach (DataRow row in dt.Rows)
       {
           string currentInvalidString = row["InvalidCharacters"].ToString();
           if (currentInvalidString.Contains(stringToCheck))
           {
               IsValidString = false;
           }
       }
       return IsValidString;
   }

Also pass datatable dt to this method

CafedeJamaica · Answer 3 · 2012-11-21T04:21:00

C#

private bool invalidUserName(string UserName)
        {
            var dt = new DataTable();
            var isvalid = from DataRow i in dt.Rows where UserName.Contains(i["invalidchars"].ToString()) select false;
            return !isvalid.Contains(false);

        }
        private bool invalidUserName(string UserName)
        {
            var dt = new DataTable();
            IEnumerable<bool> isvalid;
            isvalid =
                dt.Rows.Cast<DataRow>().Where(i => UserName.Contains(i["invalidchars"].ToString())).Select(i => false);
            return !isvalid.Contains(false);

        }

[edit]code block language corrected[/edit]

V_R · Answer 4 · 2012-11-21T20:10:00

Solution 4

Try this simple LINQ

C#

bool isInvalid = charData.AsEnumerable().Any(chr => strToValidate.Contains(chr.Field<char>("invalidChar")));

</char>

In this charData is the table of invlid characters and strToValidate is a sting to validate

Hope this will help you.

Posted 21-Nov-12 20:10pm

V_R

Validate Name using DataTable Column Values

4 solutions

Solution 1

Solution 2

Solution 3

Solution 4

Add your solution here

Preview 0