How do I find the solution of this PHP program

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This is an employee table where we have insert the data in the database but the submit button does not function

What I have tried:

<?php
include'config.php';
if(isset($_POST['submit']))
{
	$uname=$_POST['empname'];
	$gen=$_POST['gender'];
	$email=$_POST['email'];
	$con=$_POST['contact'];
	$add=$_POST['address'];
	$exp=$_POST['experience'];
	$depart=$_POST['department'];
	$edu=$_POST['education'];
	$hobby=$_POST['hobby'];
	$chk=implode('',$hobby);
	$profile=$_POST['dp'];

	$sql="INSERT into employee_info(empname,gender,email,contact,address,experience,department,education,hobby,dp) values('$uname','$gen','$email','$con','$add','$exp','depart','$edu','$check','$profile')";
	$res=mysqli_query($conn,$sql);
	if($res)
	{
		echo"form submited";
	}
}
?>

Posted 26-Apr-22 17:29pm

Aryan Jha Mar2022

Updated 26-Apr-22 21:01pm

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OriginalGriff · Answer 1 · 2022-04-26T19:47:00

Don't do it like that!
Never concatenate strings to build a SQL command. It leaves you wide open to accidental or deliberate SQL Injection attack which can destroy your entire database. Always use Parameterized queries instead.

When you concatenate strings, you cause problems because SQL receives commands like:

SQL

SELECT * FROM MyTable WHERE StreetAddress = 'Baker's Wood'

The quote the user added terminates the string as far as SQL is concerned and you get problems. But it could be worse. If I come along and type this instead: "x';DROP TABLE MyTable;--" Then SQL receives a very different command:

SQL

SELECT * FROM MyTable WHERE StreetAddress = 'x';DROP TABLE MyTable;--'

Which SQL sees as three separate commands:

SQL

SELECT * FROM MyTable WHERE StreetAddress = 'x';

A perfectly valid SELECT

SQL

DROP TABLE MyTable;

A perfectly valid "delete the table" command

SQL

--'

And everything else is a comment.
So it does: selects any matching rows, deletes the table from the DB, and ignores anything else.

So ALWAYS use parameterized queries! Or be prepared to restore your DB from backup frequently. You do take backups regularly, don't you?

Fix that through your whole app, and you may find your problem has gone as well...

Patrice T · Answer 2 · 2022-04-26T21:01:00

Quote:
but the submit button does not function

First, make sure the button calls this code.

PHP

if($res)
{
    echo"form submited";
} else {
    echo"submission failed";
}

PHP

$sql="INSERT into employee_info(empname,gender,email,contact,address,experience,department,education,hobby,dp) values('$uname','$gen','$email','$con','$add','$exp','depart','$edu','$check','$profile')";

Never build an SQL query by concatenating strings. Sooner or later, you will do it with user inputs, and this opens door to a vulnerability named "SQL injection", it is dangerous for your database and error prone.
A single quote in a name and your program crash. If a user input a name like "Brian O'Conner" can crash your app, it is an SQL injection vulnerability, and the crash is the least of the problems, a malicious user input and it is promoted to SQL commands with all credentials.
SQL injection - Wikipedia[^]
SQL Injection[^]
SQL Injection Attacks by Example[^]
PHP: SQL Injection - Manual[^]
How can I explain SQL injection without technical jargon? - Information Security Stack Exchange[^]

How do I find the solution of this PHP program

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