Round up an int when value is more than 2.5?

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Hi everyone! I've searched on google for this but nothing has helped me so does anyone know how i can round up a value from example 2.5 -> 3.0 (with integers). In my program i have a drop rate (how common it is to get a drop from a boss) and it can say that the rate is 1:6 but actually if i calculate it, it's 1:6.6 or something, then i want it to say 1:7 instead but how can i do this?

I'm using this right now:

C#

int ratecalculation = dropNumber / (int) total; //dropNumber keeps the value for all my items in the listbox, total is every items that get selected when i search for something
                    rate.Text = "Drop rate: 1:" + decimal.Round(ratecalculation, MidpointRounding.ToEven);

Posted 21-Mar-14 3:36am

Gramas19

Updated 21-Mar-14 3:38am

v4

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2 solutions

Solution 2

C#

// ***************************************************** round

// http://en.wikipedia.org/wiki/Rounding

static int round ( float parameter )
    {

    return ( ( int ) ( parameter + 0.5F ) );
    }

// ***************************************************** round

// http://en.wikipedia.org/wiki/Rounding

static int round ( double parameter )
    {

    return ( ( int ) ( parameter + 0.5 ) );
    }

Posted 21-Mar-14 19:32pm

gggustafson

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phil.o · Accepted Answer · 2014-03-21T03:39:00

Solution 1

First you need to do a REAL division, not an integer one (you do an integer division when numerator and denominator both are integers).
Then you can apply the Round() function.
This way:

C#

float ratecalculation = (float)dropNumber / total;
int roundedCalculation = (int)Math.Round(ratecalculation);

Hope this helps.

Posted 21-Mar-14 3:39am

phil.o

Updated 21-Mar-14 3:40am

v3

Comments

Gramas19 21-Mar-14 9:47am

Thank you very much, it works now! You're right, I must use a real divison to do that so i've learned something! :)

phil.o 21-Mar-14 9:49am

You're welcome. Glad to have been of any help :)