How Do I Round Off To Highest And Lowest Time

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SQL-Server-2008R2

Good Day
I want to round off time to lowest and highest time up to 5 minutes
if i have time say

09:03 if it is lowest it will round off to 09:00
And if it is highest it will round off to 09:05

Can anyone help me out

Posted 27-May-14 1:51am

surajemo

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Kornfeld Eliyahu Peter · Accepted Answer · 2014-05-27T01:57:00

Solution 1

SQL

DECLARE @MIN AS INT
SET @MIN = DATEPART(N, GETDATE())

SELECT (@MIN / 5) * 5 AS LOW, ((@MIN / 5) * 5) + 5 AS HI

Put your date in place of GETDATE()...

Posted 27-May-14 1:57am

Kornfeld Eliyahu Peter

Updated 27-May-14 1:59am

v2

Comments

surajemo 27-May-14 8:09am

Thanks you for replying
let me try it out

surajemo 27-May-14 8:21am

Kornfeld Eliyahu Peter :with the help of your solution i did it like this
declare @Roundoffvalue as int =5
declare @fromtime as time(7)='09:03'
declare @Hours as int;
set @Hours =(select datepart(HH,@fromtime))
DECLARE @MIN AS INT
SET @MIN = DATEPART(N, @fromtime)

SELECT @Hours '@Hours',

Convert(time(7),Convert(varchar(90),@Hours)+':'+Convert(varchar(90),Convert(varchar(90),(@MIN / @Roundoffvalue) * @Roundoffvalue) ))AS LOW,
Convert(time(7),Convert(varchar(90),@Hours)+':'+convert(varchar(90), ((@MIN / @Roundoffvalue) * @Roundoffvalue) + @Roundoffvalue)) AS HI

Can this be done in a more better way .

Kornfeld Eliyahu Peter 27-May-14 8:33am

You may separate computations from select, as now you have the same computations repeatedly...

surajemo 27-May-14 9:05am

You mean the hours part right