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Menubar... 4-Jul-02 4:42 4-Jul-02 4:42  How to change the menubar background color ? Dialog based appication and MDI insert roblem chen4-Jul-02 3:57 chen 4-Jul-02 3:57  Dear all, I have a dialog based application, now i want to add new parts to the application by insert a MDI project. It looks like that the MDI window should be appeared by click a button in a dialog based application. How should i do? How to deal with the problem of the dialog based main application window and the Mainfrm window? Thanks in advance! chen how to change a CDialogBar caption ? bisserke4-Jul-02 3:55 bisserke 4-Jul-02 3:55  How can I change the caption of a CDialogBar ? I tried "m_DialogBar->SetWindowText("blah blah"); " since a CDialogBar is derived from CWnd, but this doesn't seem to work. strangely this does work when I dock the dialogbar and then make it floating again. Anybody knows how come ? Or even better how tochange the caption ? thx, wouter I used to have a life ... now I have a computer Re: how to change a CDialogBar caption ? Joaquín M López Muñoz4-Jul-02 8:56 Joaquín M López Muñoz 4-Jul-02 8:56  (Just a guess) Try issuing m_DialogBar->RedrawWindow() after changing the caption. Joaquín M López Muñoz Telefónica, Investigación y Desarrollo Defining World, Projection and View Matrices Alan Chambers4-Jul-02 2:50 Alan Chambers 4-Jul-02 2:50  Hi all, got stuck on Direct3D again, already. I have created my translation, rotation, scale and concatenation matrices and would like to create a world, projection and view matrix so that I can render a triangle defined in 3d space to the screen. So far my world matrix is equivelant to the Identity matrix (1,0,0,0)(0,1,0,0)(0,0,1,0)(0,0,0,1). I have the following code for my projection and view matrix respectively: void CDXMaths::Projection(float nearplane, float farplane, float fov) { cosine = (float)cos(fov*0.5); sine = (float)sin(fov*0.5); quat = sine / (1.0f - (nearplane / farplane)); m_Projection = Empty(); m_Projection(0,0) = cosine; m_Projection(1,1) = cosine; m_Projection(2,2) = quat; m_Projection(2,3) = sine; m_Projection(3,2) = -quat * nearplane; } void CDXMaths::View(D3DVECTOR from, D3DVECTOR lookat, D3DVECTOR worldup, float roll) { m_View = Identity(); D3DVECTOR updir, rightdir, viewdir; viewdir = Normalize(lookat - from); rightdir = CrossProduct(worldup, viewdir); updir = CrossProduct(viewdir, rightdir); rightdir = Normalize(rightdir); updir = Normalize(worldup); m_View(0,0) = rightdir.x; m_View(0,1) = updir.x; m_View(0,2) = viewdir.x; m_View(1,0) = rightdir.y; m_View(1,1) = updir.y; m_View(1,2) = viewdir.y; m_View(2,0) = rightdir.z; m_View(2,1) = updir.z; m_View(2,2) = viewdir.z; m_View(3,0) = -DotProduct(rightdir, from); m_View(3,1) = -DotProduct(updir, from); m_View(3,2) = -DotProduct(viewdir, from); if (roll != 0.0f) { m_View = Multiply(RotateZ(-roll), m_View); } } For the Projection matrix I set the field of view to 60 degrees (converted to radians) with a near plane of 1.0f and a far plane of 1000.0f. For the view matrix I set the from vector to (0,0,0), the lookat vector to (0,0,1), the worldup vector to (0,1,0) and the roll to 0. I then set the D3DDevices geometry pipeline to these world, projection and view matrices (in that order, with appropriate flags). The code I then use to render is: m_pD3DDevice->SetRenderState(D3DRENDERSTATE_LIGHTING, false); if (SUCCEEDED(m_pD3DDevice->BeginScene())) { D3DLVERTEX v[3]; v[0] = D3DLVERTEX(D3DVECTOR(0,2,10), D3DRGB(1,0,0), D3DRGB(1,0,0), 0, 0); v[1] = D3DLVERTEX(D3DVECTOR(2,-2,10), D3DRGB(0,1,0), D3DRGB(1,0,0), 0, 0); v[2] = D3DLVERTEX(D3DVECTOR(-2,-2,10), D3DRGB(0,0,1), D3DRGB(1,0,0), 0, 0); m_pD3DDevice->DrawPrimitive(D3DPT_TRIANGLELIST, D3DFVF_LVERTEX, (LPVOID)v, 3, NULL); } return m_pD3DDevice->EndScene(); However, I just get a black screen. Any ideas on where I am going wrong would be much appreciated. The problem is probably in my matrices somewhere, so if you have any idea where I can get information on defining these matrices properly(except microsoft website etc. cause its crap). I'd appreciate any pointers on this topic, Many Thanks, Alan. "When I left you I was but the learner, now I am the master" - Darth Vader Decode AOL's .art image format 4-Jul-02 2:48 4-Jul-02 2:48  Hello, Do you have any idea how to decode AOL's .art file format? Is there any documentation somewhere on the Internet someone could point it to me? Thanks, Hiu Sing Ngai Re: Decode AOL's .art image format [James Pullicino]4-Jul-02 2:52 [James Pullicino] 4-Jul-02 2:52  Tried wotsit.com? Drinking In The Sun Forgot Password? graphics library emrosa4-Jul-02 2:35 emrosa 4-Jul-02 2:35  I'm looking for a graphic library for visual c++ V5.0. The intention is to plot two-dimensional graphs in a single manner and on-line processing. Thanks, Eric Manuel Rosales Pena Alfaro PhD student Unversity of Essex Wivenhoe Park Colchester, CO4 3SQ Essex, Uk email: emrosa@essex.ac.uk tel: +44-01206-87311 Re: graphics library -Dy4-Jul-02 3:07 -Dy 4-Jul-02 3:07  Hi Emrosa, I don't know if it will do exactly what your after, but have you tried the Free Image library[^]? Dylan Kenneally London, UK Re: graphics library Ravi Bhavnani4-Jul-02 9:08 Ravi Bhavnani 4-Jul-02 9:08  There are some charting controls at CP. /ravi Let's put "civil" back into "civilization" http://www.ravib.com ravib@ravib.com PGL Jonathan de Halleux9-Sep-02 1:57 Jonathan de Halleux 9-Sep-02 1:57  Try the Plot Graphic Library Cheers Jonathan de Halleux, Belgium. MULTI-DIMENSIONAL ARRAYS SEEN AS ONE-DIMENSIONAL ONE emrosa4-Jul-02 2:31 emrosa 4-Jul-02 2:31  Hello. I know that a two-dimensional array can be handles as one-dimensional array by converting the indexes to a single one. Supose you have the following: int *table; table=new int table[3*3]; When referencig table[2][2] by a single index index=(2*3+2); then table[index] can be recalled. Now, I'm having a three-dimensional array and because is faster to handle dynamic arrays, I can define it as: int table1; table1=new int table[3*3*3]; but I got lost finding the index conversion formulae... Eric Manuel Rosales Pena Alfaro PhD student Unversity of Essex Wivenhoe Park Colchester, CO4 3SQ Essex, Uk email: emrosa@essex.ac.uk tel: +44-01206-87311 Re: MULTI-DIMENSIONAL ARRAYS SEEN AS ONE-DIMENSIONAL ONE Alan Chambers4-Jul-02 3:28 Alan Chambers 4-Jul-02 3:28  Your old formulae was xPos + (yPos x Height). I believe your new formulae would therefore be: (xPos + (yPos x Width)) + (zPos x (Height x Width)). This could probably be further reduced. "When I left you I was but the learner, now I am the master" - Darth Vader Re: MULTI-DIMENSIONAL ARRAYS SEEN AS ONE-DIMENSIONAL ONE emrosa4-Jul-02 4:18 emrosa 4-Jul-02 4:18  Thanks for your help....I tried that but it did not work...however, you gave an idea and I put myself to think deeply and I just found this: Let be a multidimensional array MArray[max1stdim][max2nddim]...[maxnthdim], the indexes referencing certain location be i1,i2,...,in. If MArray is declared as int MArray[max1stdim*max2nddim*...*maxnthdim]; then the index referencing the location (i1,i2,...in-1,in) will be: index=(i1*max2nddim*max3rddim*...*maxnthdim)+(i2*max3rddim*...*maxnthdim)+...+(in-1)*maxnthdim+in Then for an array MArray[4][3][2] declared as MArray[3*3*3], the single index to reference (i,j,k)will be: index=(i*4*3)+(j*2)+k I have tried this and it works! Thanks again..... Eric Manuel Rosales Pena Alfaro PhD student Unversity of Essex Wivenhoe Park Colchester, CO4 3SQ Essex, Uk email: emrosa@essex.ac.uk tel: +44-01206-87311 Re: MULTI-DIMENSIONAL ARRAYS SEEN AS ONE-DIMENSIONAL ONE Alan Chambers4-Jul-02 5:56 Alan Chambers 4-Jul-02 5:56  Can ask one question? how can you have "an array MArray[4][3][2] declared as MArray[3*3*3]"? If you are trying to access the 3*3*3 MArray at position [4][3][2] using a single index then that is impossible, because the rows and columns will be indexed from 0 through to 2 for each x,y and z column, so 4 and 3 are invalid index positions. If you were trying to access the last record in a 3*3*3 matrix, the single index value you require is 26 (0 to 8, 9 to 17, 18 to 26). Using my equation earlier, if you were trying to index the last position in the 3d array, so XPos = 2, YPos = 2 and ZPos = 2, you would get: (2 + (2 * 3)) + (2 * 3 * 3)) = 26. the index position you desire. Martin has implemented the coded version of the equation (but in the opposite direction to the way I wrote my equation) : b[i*(d2*d3) + j*d3 + k] = x; i = ZPos j = YPos k = XPos d2 = Height d3 = Width *Please note I made a small error before when I wrote (yPos + Height), this is probably why you couldn't get it to work, it should have read (yPos + Width), which I have now changed it to. Without this correction the formula would only *work* if the 3d array was a cube. It should now work regardless of dimensions. Alan. "When I left you I was but the learner, now I am the master" - Darth Vader Re: MULTI-DIMENSIONAL ARRAYS SEEN AS ONE-DIMENSIONAL ONE 4-Jul-02 11:25 4-Jul-02 11:25  Sorry for the mistake...the dimensions of the array MArray[4][3][2] declared as MAarray[4*3*2]...and trying to access element Marray(3,3,2).... The rest of the formula is correct and your correction as well... Thanks, Re: MULTI-DIMENSIONAL ARRAYS SEEN AS ONE-DIMENSIONAL ONE Martin Ziacek4-Jul-02 3:43 Martin Ziacek 4-Jul-02 3:43  Try this: int d1 = 3; int d2 = 4; int d3 = 5; BYTE x = 0; BYTE *b = new BYTE[d1*d2*d3]; for (int i = 0; i < d1; i++) { for (int j = 0; j < d2; j++) { for (int k = 0; k < d3; k++) { b[i*(d2*d3) + j*d3 + k] = x; x++; } } } I hope it does what you need. Re: MULTI-DIMENSIONAL ARRAYS SEEN AS ONE-DIMENSIONAL ONE emrosa4-Jul-02 4:20 emrosa 4-Jul-02 4:20  Thanks for your help....I have tried that and it did work...therefore, making a generalization for this, I just found this: Let be a multidimensional array MArray[max1stdim][max2nddim]...[maxnthdim], the indexes referencing certain location be i1,i2,...,in. If MArray is declared as int MArray[max1stdim*max2nddim*...*maxnthdim]; then the index referencing the location (i1,i2,...in-1,in) will be: index=(i1*max2nddim*max3rddim*...*maxnthdim)+(i2*max3rddim*...*maxnthdim)+...+(in-1)*maxnthdim+in Then for an array MArray[4][3][2] declared as MArray[3*3*3], the single index to reference (i,j,k)will be: index=(i*4*3)+(j*2)+k I have tried this and it works! Thanks again..... Eric Manuel Rosales Pena Alfaro PhD student Unversity of Essex Wivenhoe Park Colchester, CO4 3SQ Essex, Uk email: emrosa@essex.ac.uk tel: +44-01206-87311 Re: MULTI-DIMENSIONAL ARRAYS SEEN AS ONE-DIMENSIONAL ONE Martin Ziacek4-Jul-02 4:41 Martin Ziacek 4-Jul-02 4:41  Would be nice if you will write article about it and compare performance between different types of allocations and accesseing that memory. Re: MULTI-DIMENSIONAL ARRAYS SEEN AS ONE-DIMENSIONAL ONE emrosa4-Jul-02 4:46 emrosa 4-Jul-02 4:46  How will I do that? What allocation and accesing methods?. Where will I submit the article?...Would you like to help me? Thanks, Eric Manuel Rosales Pena Alfaro PhD student Unversity of Essex Wivenhoe Park Colchester, CO4 3SQ Essex, Uk email: emrosa@essex.ac.uk tel: +44-01206-87311 Re: MULTI-DIMENSIONAL ARRAYS SEEN AS ONE-DIMENSIONAL ONE Martin Ziacek4-Jul-02 4:53 Martin Ziacek 4-Jul-02 4:53  I understood you think addressing multi-dimensional array with one index you are computing by yourself is a faster method than addressing multi-dimensional array with pointers. So what I think is a demonstration program using two arrays of the same size but different access methods and allocation and comparison between speeds. And obviously, you will submit article with that demo program here at CP. Link before compile (?) in MSDev Cristian Amarie4-Jul-02 1:47 Cristian Amarie 4-Jul-02 1:47  Can anyone let me know why I see 'Linking...' and after this 'Compiling...' ? Thank you. [Sample] --------------------Configuration: Shared - Win32 Release-------------------- Compiling... EnumString.cpp Linking... Creating library .\Release/Shared.lib and object .\Release/Shared.exp LINK : warning LNK4089: all references to "IMAGEHLP.dll" discarded by /OPT:REF Compiling... Report.cpp Report2.cpp ReportPreviewWnd.cpp Shared.cpp Generating Code... Shared.dll - 0 error(s), 3 warning(s) Re: Link before compile (?) in MSDev Jeremy Pullicino4-Jul-02 1:50 Jeremy Pullicino 4-Jul-02 1:50  Your monitor might be upside down... "Hey man, Taliban, Tali me Banana." Re: Link before compile (?) in MSDev Tibor Blazko4-Jul-02 1:51 Tibor Blazko 4-Jul-02 1:51  i guess slow refresh rate t! Re: Link before compile (?) in MSDev Tibor Blazko4-Jul-02 3:56 Tibor Blazko 4-Jul-02 3:56  big sorry, i did not realize current forum hm, it me already happened too (no your action after build run?), do not worry t!

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