How to add new record in XML file with C#

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Hi,
I am facing problem about adding new record on my xml file.
Let's say I have this plist.xml file:

XML

<Project>
  <ProjectDetail id="0">
    <title>Batman vs Superman</title>
    <platform>TV OS</platform>
    <code>5504</code>
    <dbname>BVSM</dbname>
  </ProjectDetail>
</Project>

What I want is to add new record on that XML file:
- ProjectDetail id = "1"
- title = Cartman and Stan
- platform = TV OS
- code = 1045
- dbname = CAS

So it would looks like this:

XML

<Project>
  <ProjectDetail id="0">
    <title>Batman vs Superman</title>
    <platform>TV OS</platform>
    <code>5504</code>
    <dbname>BVSM</dbname>
  </ProjectDetail>
<ProjectDetail id="1">
    <title>Cartman and Stan</title>
    <platform>TV OS</platform>
    <code>1048</code>
    <dbname>CAS</dbname>
  </ProjectDetail>
</Project>

Anyone can give me insight?

What I have tried:

I googled so many things, but since this is my first work with XML I confuse where to start.

I tried this

XmlElement elem = doc.CreateElement("ProjectDetail");
elem.InnerText = "1";
doc.CreateElement("title");
elem.InnerText = "Cartman and Stan";

root.AppendChild(elem);
doc.Save(frm1.filedata);

But the result is wrong.

Posted 23-Mar-16 22:47pm

satrio_budidharmawan

Updated 23-Mar-16 23:07pm

v3

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FARONO 24-Mar-16 4:57am

you should Google "XmlElement", Serialization or XmlDocument.. I'm sure there are plenty of examples..

(http://stackoverflow.com/questions/9761363/adding-to-xml-file)

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Maciej Los · Answer 1 · 2016-03-23T23:07:00

There's few ways to achieve that:
1) using System.Xml.Linq classes: XDocument[^] + XElement[^] + XAttribute[^]:

C#

string xcontent = @"<Project>
  <ProjectDetail id='0'>
    <title>Batman vs Superman</title>
    <platform>TV OS</platform>
    <code>5504</code>
    <dbname>BVSM</dbname>
  </ProjectDetail>
</Project>";

//just for example
XDocument xdoc = XDocument.Parse(xcontent);
//you should use:
//XDocument xdoc = XDocument.Load("FullFileName.xml");

XElement xele = new XElement("ProjectDetail", new XAttribute("id", 1),
	new XElement("title", "Cartman and Stan"),
	new XElement("platform", "TV OS"), 
	new XElement("code", 1048),
	new XElement("dbname", "CAS"));

xdoc.Root.Add(xele);
xdoc.Save("FullFileName.xml");

2) using System.Xml classes: XmlReader[^] + XmlWriter[^]

3) using Xml Serialization and Deserialization
Introducing XML Serialization[^]
Examples of XML Serialization[^]
XML Serialization and Deserialization: Part-1[^]
XML Serialization and Deserialization: Part-2[^]
A Complete Sample of Custom Class Collection Serialization and Deserialization[^]

Try!

Patrice T · Answer 2 · 2016-03-23T23:00:00

Solution 2

Quote:
I confuse where to start.

Start with Google and search an XLM reader/writer library.
Feel free do read documentation and follow tutorials too.
Sorry no time to do search for you.

Posted 23-Mar-16 23:00pm

Patrice T

RickZeeland · Answer 3 · 2016-03-23T22:56:00

Although Xdocument is mostly used, I think in your case Xelement is easier to use, here are some examples: XElement Class Overview[^]

XElement contacts =
new XElement("Contacts",
    new XElement("Contact",
        new XElement("Name", "Patrick Hines"), 
        new XElement("Phone", "206-555-0144"),
        new XElement("Address",
            new XElement("Street1", "123 Main St"),
            new XElement("City", "Mercer Island"),
            new XElement("State", "WA"),
            new XElement("Postal", "68042")
        )
    )
);

C#

// This is an WPF example !
private XElement xmlSource;

C#

// Set the datagrid source to XML file.
this.xmlSource = XElement.Load(this.fileName);
this.DataGrid1.DataContext = this.xmlSource;

C#

this.xmlSource.Save(this.fileName);

How to add new record in XML file with C#

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